password generator which ask number of letter number and symbols [duplicate]

The difficult thing with passwords is to make them strong enough and still be able to remember them. If the password is not meant to be remembered by a human being, then it is not really a password.

You use Python's os.urandom(): that's good. For any practical purpose (even cryptography), the output of os.urandom() is indistinguishable from true alea. Then you use it as seed in random, which is less good: that one is a non-cryptographic PRNG, and its output may exhibit some structure which will not register in a statistical measurement tool, but might be exploited by an intelligent attacker. You should work with os.urandom() all along. To make things simple: choose an alphabet of length 64, e.g. letters (uppercase and lowercase), digits, and two extra punctuation characters (such as '+' and '/'). Then, for each password character, get one byte from os.urandom(), reduce the value modulo 64 (this is unbiased because 64 divides 256) and use the result as index in your chars array.

With an alphabet of length 64, you get 6 bits of entropy per character (because 2⁶ = 64). Thus, with 13 characters, you get 78 bits of entropy. This is not ultimately strong in all cases, but already very strong (it could be defeated with a budget which will be counted in months and billions of dollars, not mere millions).

XKCD has a great explanation of why what you think are strong passwords aren't.

To anyone who understands information theory and security and is in an infuriating argument with someone who does not (possibly involving mixed case), I sincerely apologize. - Randall Munroe

And if you don't understand the math behind what this illustration is explaining, don't try writing anything that should be cryptographically secure, because it won't be. Just put the mouse down and step away from the keyboard.