Solution 1:
Use the full path to the file instead of just the name of the file and it should work fine For example:
with open(r'E:\Project\level'+str(n+3)+'.txt', 'w+') as f:
Use the full path to the file instead of just the name of the file and it should work fine For example:
with open(r'E:\Project\level'+str(n+3)+'.txt', 'w+') as f: