can we build a dynamic url in laravel, which can include the blade file dynamicly

Iam trying to build an easy method to build a laravel project. I got from articles that we should build controller and blade file for example this command php artisan make:livewire Admin.CourseList if we had a lot of page it's going to be lot of file,

so i hava a questions can we just build one controller to use in a lot of blade file, the idea is making dynamic url, then the url detected in controller, controller get data from url to fetch the blade file.

Iam trying to use this method

Route::get('master/{fileis}', Master::class); ( my route )

<?php
// master controller
namespace App\Http\Livewire\Admin;

use Livewire\Component;

class Master extends Component 
{
   public function index ($field)
   {
      return view('livewire.admin.$filed');
   }
}

I wish that when url with $field are going to be the file name.

So the effect i wish for example mywebsite.com/master/login-file, this url going to fetch login-file.blade. but it's didn't work.

Solution 1:

There a many typo in your question, but i got what you mean.

Try This.

// in route
Route::get('/{$field}', [Master::class, 'index']);

// master index()
public function index ($field)
{
   // `double quote` for `var` inside `string`
   return view("livewire.admin.$field");
}

Remember to create necessary view or add if with logical View::exists('your_view') in your view call

EDIT: in LARAVEL LIVEWIRE

I'll give you some picture.

run php artisan make:livewire admin.course

// in route
Route::livewire('/course/{course}', 'admin.course');

// in Course.php
class Course extends Component
{
    public $course;

    public function mount($course)
    {
        // init course in mount cycle
        $this->course = $course;
    }

    public function render()
    {
        // insert `public $coursea` to your `view`
        return view("livewire.admin.$this->course", [
            'course' => $this->course,
        ]);
    }
}