Get contacts in Android without duplicates

Solution 1:

You should rather create a POJO Object and than assign the data into it and return a list of that POJO Object and then you can make use of distinct extension on the list to get a filtered result they way you want it . This is how you can achieve what you want :

Create a POJO Object :

data class Contact(
val id : String ,
val name : String, 
val number : String)

And then when retrieveing the data you can do the following :

   @SuppressLint("Range")
    
    fun getNamePhoneDetails(): MutableList<Contact>? {
        val names = MutableList<Contact>()
        val cr = contentResolver
        val cur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
            null, null, null)
        if (cur!!.count > 0) {
            while (cur.moveToNext()) {
                val id = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NAME_RAW_CONTACT_ID))
                val name = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME))
                val number = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))
                names.add(Contact(id , name , number))
            }
        }
        return names
    }

And then while retreiving the data you need to just filter the list in the following manner :

 val list = getNamePhoneDetails()
 list.distinctBy { it.number }.forEach { println(it) }

Get contacts in Android without duplicates

Solution 1:

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