Remove items from an array in order until matching item is found

I have an array of items

const test = [
  {
    id: '1',
  },
  {
    id: 'a',
  },
  {
    id: '3',
  },
  {
    id: 'b',
  },
  {
    id: '5',
  },
  {
    id: 'c',
  },
  {
    id: '7',
  },
];

These objects are always going to be in the same order. I'd like to be able to remove all items in order from the start until a specific id is reached.

I thought I could do this by just looping through until one is found and then pushing the items coming after that to a separate array:

let skippedArray = []

let skipUntilIndex = undefined

test.forEach((item, i) => {
  if(item.id === 'b') {
    skipUntilIndex = i
  }
  if(skipUntilIndex && i >= skipUntilIndex) {
    skippedArray.push(item)
  }
})

// [
//   {
//     id: 'b',
//   },
//   {
//     id: '5',
//   },
//   {
//     id: 'c',
//   },
//   {
//     id: '7',
//   },
// ]
console.log(skippedArray)

But this seems pretty dirty. Is there a better way to achieve this? I don't mind using lodash or similar libraries.

Solution 1:

You can do it by using findIndex and slice methods, by findIndex you can find the index of target item in the array and with slice you can make a subArray of your original Array.

const data = [ { id: '1', }, { id: 'a', }, { id: '3', }, { id: 'b', }, { id: '5', }, { id: 'c', }, { id: '7', }, ];

const getSkippedItems = (id)=> {
    const index = data.findIndex(v => v.id == id);
    return index > -1 ? data.slice(index) : [];
}

const skippedArr = getSkippedItems('b');
console.log(skippedArr)