Extract file name with the folder containing the file

If I have the following file path:

'G:\\My Drive\\A\\B\\C\\EH\\2021_12_17.txt'

How can I get the file name with the folder containing the file:

'EH\\2021_12_17.txt'

Solution 1:

You can apply pathlib here:

from pathlib import Path

path = Path(r'G:\My Drive\A\B\C\EH\2021_12_17.txt')
result = path.relative_to(path.parents[1])

P.S. Use str() if you need string result.

Try join with str.split

path = 'G:\\My Drive\\A\\B\\C\\EH\\2021_12_17.txt'
'\\'.join(path.split('\\')[-2:])  # -> 'EH\\2021_12_17.txt'