javascript sort with unicode

Solution 1:

If the locale in your system is set correctly then you can use localeCompare method instead of greater-than operator to compare the strings - this method is locale aware.

function sortComparer(a,b){
    return a.title.localeCompare(b.title)
};

Solution 2:

For sorting an array with custom setting do as following:

1. Create an array with a custom order of alphabets:

   var alphabets = ["A", "B", "C", "Č", "Ć", "D","Dž","Đ","E","F","G","H","I","J","K","L","Lj","M","N","Nj","O","P","R","S", "ÛŒ","T","U","V","Z","Ž"];

2. Create a list of test array:

   var testArrray = ["B2","D6","A1","Ć5","Č4","C3"];

3. Create a sort function name:

   function OrderFunc(){
             testArrray.sort(function (a, b) {
                 return CharCompare(a, b, 0);
             });
         }
   

4. create the CharCompare function(index: sort "AAAB" before "AAAC"):

    function CharCompare(a, b, index) {
     if (index == a.length || index == b.length)
         return 0;
     //toUpperCase: isn't case sensitive
     var aChar = alphabets.indexOf(a.toUpperCase().charAt(index));
     var bChar = alphabets.indexOf(b.toUpperCase().charAt(index));
     if (aChar != bChar)
         return aChar - bChar
     else
         return CharCompare(a,b,index+1)
   

   }

5. Call OrderFunc for sorting the testArray(the result will be : A1,B2,C3,Č4,Ć5,D6).

Test Online

Good Luck