Is it possible to create a multi-line string variable in a Makefile
Yes, you can use the define keyword to declare a multi-line variable, like this:
define ANNOUNCE_BODY
Version $(VERSION) of $(PACKAGE_NAME) has been released.
It can be downloaded from $(DOWNLOAD_URL).
etc, etc.
endef
The tricky part is getting your multi-line variable back out of the makefile. If you just do the obvious thing of using "echo $(ANNOUNCE_BODY)", you'll see the result that others have posted here -- the shell tries to handle the second and subsequent lines of the variable as commands themselves.
However, you can export the variable value as-is to the shell as an environment variable, and then reference it from the shell as an environment variable (NOT a make variable). For example:
export ANNOUNCE_BODY
all:
@echo "$$ANNOUNCE_BODY"
Note the use of $$ANNOUNCE_BODY
, indicating a shell environment variable reference, rather than $(ANNOUNCE_BODY)
, which would be a regular make variable reference. Also be sure to use quotes around your variable reference, to make sure that the newlines aren't interpreted by the shell itself.
Of course, this particular trick may be platform and shell sensitive. I tested it on Ubuntu Linux with GNU bash 3.2.13; YMMV.
Another approach to 'getting your multi-line variable back out of the makefile' (noted by Eric Melski as 'the tricky part'), is to plan to use the subst
function to replace the newlines introduced with define
in your multi-line string with \n
. Then use -e with echo
to interpret them. You may need to set the .SHELL=bash to get an echo that does this.
An advantage of this approach is that you also put other such escape characters into your text and have them respected.
This sort of synthesizes all the approaches mentioned so far...
You wind up with:
define newline
endef
define ANNOUNCE_BODY
As of $(shell date), version $(VERSION) of $(PACKAGE_NAME) has been released.
It can be downloaded from $(DOWNLOAD_URL).
endef
someTarget:
echo -e '$(subst $(newline),\n,${ANNOUNCE_BODY})'
Note the single quotes on the final echo are crucial.
Assuming you only want to print the content of your variable on standard output, there is another solution :
do-echo:
$(info $(YOUR_MULTILINE_VAR))