What is the quickest way to HTTP GET in Python?
What is the quickest way to HTTP GET in Python if I know the content will be a string? I am searching the documentation for a quick one-liner like:
contents = url.get("http://example.com/foo/bar")
But all I can find using Google are httplib
and urllib
- and I am unable to find a shortcut in those libraries.
Does standard Python 2.5 have a shortcut in some form as above, or should I write a function url_get
?
- I would prefer not to capture the output of shelling out to
wget
orcurl
.
Solution 1:
Python 3:
import urllib.request
contents = urllib.request.urlopen("http://example.com/foo/bar").read()
Python 2:
import urllib2
contents = urllib2.urlopen("http://example.com/foo/bar").read()
Documentation for urllib.request
and read
.
Solution 2:
You could use a library called requests.
import requests
r = requests.get("http://example.com/foo/bar")
This is quite easy. Then you can do like this:
>>> print(r.status_code)
>>> print(r.headers)
>>> print(r.content)
Solution 3:
If you want solution with httplib2 to be oneliner consider instantiating anonymous Http object
import httplib2
resp, content = httplib2.Http().request("http://example.com/foo/bar")
Solution 4:
Have a look at httplib2, which - next to a lot of very useful features - provides exactly what you want.
import httplib2
resp, content = httplib2.Http().request("http://example.com/foo/bar")
Where content would be the response body (as a string), and resp would contain the status and response headers.
It doesn't come included with a standard python install though (but it only requires standard python), but it's definitely worth checking out.