Removing empty rows of a data file in R
Solution 1:
I assume you want to remove rows that are all NAs. Then, you can do the following :
data <- rbind(c(1,2,3), c(1, NA, 4), c(4,6,7), c(NA, NA, NA), c(4, 8, NA)) # sample data
data
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 1 NA 4
[3,] 4 6 7
[4,] NA NA NA
[5,] 4 8 NA
data[rowSums(is.na(data)) != ncol(data),]
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 1 NA 4
[3,] 4 6 7
[4,] 4 8 NA
If you want to remove rows that have at least one NA, just change the condition :
data[rowSums(is.na(data)) == 0,]
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 4 6 7
Solution 2:
If you have empty rows, not NAs, you can do:
data[!apply(data == "", 1, all),]
To remove both (NAs and empty):
data <- data[!apply(is.na(data) | data == "", 1, all),]
Solution 3:
Here are some dplyr
options:
# sample data
df <- data.frame(a = c('1', NA, '3', NA), b = c('a', 'b', 'c', NA), c = c('e', 'f', 'g', NA))
library(dplyr)
# remove rows where all values are NA:
df %>% filter_all(any_vars(!is.na(.)))
df %>% filter_all(any_vars(complete.cases(.)))
# remove rows where only some values are NA:
df %>% filter_all(all_vars(!is.na(.)))
df %>% filter_all(all_vars(complete.cases(.)))
# or more succinctly:
df %>% filter(complete.cases(.))
df %>% na.omit
# dplyr and tidyr:
library(tidyr)
df %>% drop_na
Solution 4:
Alternative solution for rows of NA
s using janitor
package
myData %>% remove_empty("rows")
Solution 5:
This is similar to some of the above answers, but with this, you can specify if you want to remove rows with a percentage of missing values greater-than or equal-to a given percent (with the argument pct
)
drop_rows_all_na <- function(x, pct=1) x[!rowSums(is.na(x)) >= ncol(x)*pct,]
Where x
is a dataframe and pct
is the threshold of NA
-filled data you want to get rid of.
pct = 1
means remove rows that have 100% of its values NA
.
pct = .5
means remome rows that have at least half its values NA