Evaluating the end time of a period of time

hour = int(input("Starting time (hours): "))
mins = int(input("Starting time (minutes): "))
dura = int(input("Event duration (minutes): "))
time_hour = (hour + dura//60 + (mins+ dura%60)//60)%24
time_min = (mins+ dura%60)%60
print("It will end at " + str(time_hour) + ":" + str(time_min))

It will end at 13:16

Try this:

from datetime import date, datetime, time, timedelta


if __name__ == '__main__':
    hour = int(input("Starting time (hours): "))
    mins = int(input("Starting time (minutes): "))
    dura = int(input("Event duration (minutes): "))
    dt = datetime.combine(date.today(), time(hour, mins)) + timedelta(minutes=dura)
    print(dt.time().strftime("%H:%M"))

Output: 13:16

I understand this has been answered. However I ran across this exact problem in some practice work for learning python. The end result just wanted the time in HH:mm format.

#given hour = 12 , mins = 17 , dura = 59

hour = int(input("Starting time (hours): "))
mins = int(input("Starting time (minutes): "))
dura = int(input("Event duration (minutes): "))
hour = (hour + dura//60 + (mins+ dura%60)//60)%24
mins = (mins+ dura%60)%60
print(hour,":",mins,sep="")

13:16

The last line was requested like this. I understand this was largely explained and answered, but I saw a difference in syntax and wanted to share my results.