Proving $\displaystyle\lim_{h\to0}\frac{f(x+h)-2f(x)+f(x-h)}{h^2}=f''(x)$

We write the Taylor series:

$$f(x+h)=f(x)+hf'(x)+\frac{h^2}{2}f''(x)+h^2\epsilon(h)\tag{1}$$ and $$f(x-h)=f(x)-hf'(x)+\frac{h^2}{2}f''(x)+h^2\epsilon'(h)\tag{2}$$ where $$\lim_{h\to0}\epsilon (h)=\lim_{h\to0}\epsilon' (h)=0$$ so add the two equalities $(1)$ and $(2)$ and you find the result easily.