How can I add moving effects to my controls in C#?

Solution 1:

Window animation is a built-in feature for Windows. Here's a class that uses it:

using System;
using System.ComponentModel;
using System.Windows.Forms;
using System.Runtime.InteropServices;

public static class Util {
    public enum Effect { Roll, Slide, Center, Blend }

    public static void Animate(Control ctl, Effect effect, int msec, int angle) {
        int flags = effmap[(int)effect];
        if (ctl.Visible) { flags |= 0x10000; angle += 180; }
        else {
            if (ctl.TopLevelControl == ctl) flags |= 0x20000; 
            else if (effect == Effect.Blend) throw new ArgumentException();
        }
        flags |= dirmap[(angle % 360) / 45];
        bool ok = AnimateWindow(ctl.Handle, msec, flags);
        if (!ok) throw new Exception("Animation failed");
        ctl.Visible = !ctl.Visible;
    }

    private static int[] dirmap = { 1, 5, 4, 6, 2, 10, 8, 9 };
    private static int[] effmap = { 0, 0x40000, 0x10, 0x80000 };

    [DllImport("user32.dll")]
    private static extern bool AnimateWindow(IntPtr handle, int msec, int flags);
}

Sample usage:

    private void button2_Click(object sender, EventArgs e) {
        Util.Animate(button1, Util.Effect.Slide, 150, 180);
    }

Solution 2:

If you are using .NET 4 (if not replace Task with Thread), a function similar to this could be a start:

    private void slideToDestination(Control destination, Control control, int delay, Action onFinish)
    {
        new Task(() =>
        {
            int directionX = destination.Left > control.Left ? 1 : -1;
            int directionY = destination.Bottom > control.Top ? 1 : -1;

            while (control.Left != destination.Left || control.Top != destination.Bottom)
            {
                try
                {
                    if (control.Left != destination.Left)
                    {
                        this.Invoke((Action)delegate()
                        {
                            control.Left += directionX;
                        });
                    }
                    if (control.Top != destination.Bottom)
                    {
                        this.Invoke((Action)delegate()
                        {
                            control.Top += directionY;
                        });
                    }
                    Thread.Sleep(delay);
                }
                catch
                {
                    // form could be disposed
                    break;
                }
            }

            if (onFinish != null) onFinish();

        }).Start();
    }

Usage:

slideToDestination(sender as Control, panel1, 10, () => MessageBox.Show("Done!"));
slideToDestination(sender as Control, panel1, 0, null);

As action you would send some boolean variable to set to true so that you know that the animation has finished or some code to run after it. Beware of deadlocks when calling with a null action. You could run two animations on the same control in two different directions with the same speed, and it will stay where it was forever and of course two animations simultaneusly can make the control go infinitely in some direction because the while will never finish :)