print specific line and then some more

I am trying to search a file for a pattern and if the it is found I want to see the line and 10 more lines of the result.

so far I have

grep -n pattern file | cut -d: f1 

now not sure how to use this out put to do the print with the logic like

sed -n result,(result+10)p file

probably going to have a few issued if it pattern is in multiple lines.

Any help is appreciated

Using grep 2.10:

grep -A 10 "pattern" your_file

will print 10 lines after the match

From the grep man page:

-A num

--after-context=num

Print num lines of trailing context after matching lines.

Using GNU awk 3.1.8:

awk '{if(a-->0) {print; next}} /pattern/{print; a=10}' your_file