Printing the correct number of decimal points with cout

With <iomanip>, you can use std::fixed and std::setprecision

Here is an example

#include <iostream>
#include <iomanip>

int main()
{
    double d = 122.345;

    std::cout << std::fixed;
    std::cout << std::setprecision(2);
    std::cout << d;
}

And you will get output

122.34

You were nearly there, need to use std::fixed as well, refer http://www.cplusplus.com/reference/iostream/manipulators/fixed/

#include <iostream>
#include <iomanip>

int main(int argc, char** argv)
{
    float testme[] = { 0.12345, 1.2345, 12.345, 123.45, 1234.5, 12345 };

    std::cout << std::setprecision(2) << std::fixed;

    for(int i = 0; i < 6; ++i)
    {
        std::cout << testme[i] << std::endl;
    }

    return 0;
}

outputs:

0.12
1.23
12.35
123.45
1234.50
12345.00

setprecision(n) applies to the entire number, not the fractional part. You need to use the fixed-point format to make it apply to the fractional part: setiosflags(ios::fixed)

Simplify the accepted answer

Simplified example:

#include <iostream>
#include <iomanip>

int main()
{
    double d = 122.345;
    std::cout << std::fixed << std::setprecision(2) << d;
}

And you will get output

122.34

Reference:

• std::fixed
• std::setprecision

#include<stdio.h>
int main()

{

 double d=15.6464545347;

printf("%0.2lf",d);

}