Two arrays in foreach loop

I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.

This is an example:

<?php
    $codes = array('tn','us','fr');
    $names = array('Tunisia','United States','France');

    foreach( $codes as $code and $names as $name ) {
        echo '<option value="' . $code . '">' . $name . '</option>';
    }
?>

This method didn't work for me. Any suggestions?

foreach( $codes as $code and $names as $name ) { }

That is not valid.

You probably want something like this...

foreach( $codes as $index => $code ) {
   echo '<option value="' . $code . '">' . $names[$index] . '</option>';
}

Alternatively, it'd be much easier to make the codes the key of your $names array...

$names = array(
   'tn' => 'Tunisia',
   'us' => 'United States',
   ...
);

foreach operates on only one array at a time.

The way your array is structured, you can array_combine() them into an array of key-value pairs then foreach that single array:

foreach (array_combine($codes, $names) as $code => $name) {
    echo '<option value="' . $code . '">' . $name . '</option>';
}

Or as seen in the other answers, you can hardcode an associative array instead.

Use array_combine() to fuse the arrays together and iterate over the result.

$countries = array_combine($codes, $names);

Use an associative array:

$code_names = array(
                    'tn' => 'Tunisia',
                    'us' => 'United States',
                    'fr' => 'France');

foreach($code_names as $code => $name) {
   //...
}

I believe that using an associative array is the most sensible approach as opposed to using array_combine() because once you have an associative array, you can simply use array_keys() or array_values() to get exactly the same array you had before.