'package.json' is not under 'rootDir'
Solution 1:
This is possible, and it turns out, not hard.
The reason the solution is not obvious is because typescript relies on the rootDir
to decide the directory structure of the output (see this comment from Typescript's bossman), and only code included in the output or in package dependencies can be imported.
- If you set
rootDir
to the root of your project,package.json
gets emitted to the root ofoutDir
and can be imported. But then your compiledsrc
files get written tooutDir/src
. - If you set
rootDir
tosrc
, files in there will compile to the root ofoutDir
. But now the compiler won't have a place to emitpackage.json
, so it issues "an error because the project appears to be misconfigured" (bossman's words).
solution: use separate Typescript sub-projects
A Typescript project is defined by a tsconfig file, is self-contained, and is effectively bounded by its rootDir
. This is a very good thing, as it lines up with principles of encapsulation.
You can have multiple projects (e.g. a main and a set of libs) each in their own directory and with their own tsconfig. Dependencies between them are declared in the tsconfig file using Typescript Project References.
I admit, the term "projects" is a poor one, as intuitively it refers to the whole shebang, but "modules" and "packages" are already taken in this context. Think of them as "subprojects" and it will make more sense.
We'll treat the src
directory and the root directory containing package.json
as separate projects. Each will have its own tsconfig
file.
-
Give the
src
dir its own project../src/tsconfig.json
:{ "compilerOptions": { "rootDir": ".", "outDir": "../dist/", "resolveJsonModule": true }, "references": [ // this is how we declare a dependency from { "path": "../" } // this project to the one at the root dir` ] }
-
Give the root dir its own project.
./tsconfig.json
:{ "compilerOptions": { "rootDir": ".", "outDir": ".", // if out path for a file is same as its src path, nothing will be emitted "resolveJsonModule": true, "composite": true // required on the dependency project for references to work }, "files": [ // by whitelisting the files to include, TS won't automatically "package.json" // include all source below root, which is the default. ] }
-
run
tsc --build src
and voilà!This will build the
src
project. Because it declares a reference to the root project, it will build that one also, but only if it is out of date. Because the root tsconfig has the same dir as theoutDir
, tsc will simply do nothing topackage.json
, the one file it is configured to compile.
this is great for monorepos
You can isolate modules/libraries/sub-projects by putting them in their own subdirectory and giving them their own tsconfig.
-
You can manage dependencies explicitly using Project References, as well as modularize the build:
From the linked doc:
- you can greatly improve build times
A long-awaited feature is smart incremental builds for TypeScript projects. In 3.0 you can use the
--build
flag withtsc
. This is effectively a new entry point fortsc
that behaves more like a build orchestrator than a simple compiler.Running
tsc --build
(tsc -b
for short) will do the following:- Find all referenced projects
- Detect if they are up-to-date
- Build out-of-date projects in the correct order
Don’t worry about ordering the files you pass on the commandline -
tsc
will re-order them if needed so that dependencies are always built first.enforce logical separation between components
organize your code in new and better ways.
It's also very easy:
-
src/tsconfig.json
Even if you have no code at the root, this tsconfig can be where all the common settings go (the others will inherit from it), and it will enable a simple
tsc --build src
to build the whole project (and with--force
to build it from scratch).{ "compilerOptions": { "rootDir": ".", "outDir": "../build/", "resolveJsonModule": true, "composite": true }, // this root project has no source of its own "files": [], // but building this project will build all of the following: "references": [ { "path": "./common" } { "path": "./projectA" } // include all other sub-projects here ] }
-
src/common/tsconfig.json
Because common has no references, imports are limited to targets within its directory and
npm_modules
. You could even restrict the latter, I believe, by giving it its ownpackage.json
.{ "compilerOptions": { "rootDir": ".", "outDir": "../../build/common", "resolveJsonModule": true, "composite": true } }
-
src/projectA/tsconfig.json
projectA can import common because of the declared reference.
{ "compilerOptions": { "rootDir": ".", "outDir": "../../build/libA", "resolveJsonModule": true, "composite": true }, "references": [ { "path": "../common" } ] }
-
Solution 2:
We can set resolveJsonModule
to false and declare a module for *.json
inside typings.d.ts
which will require JSON files as modules and it will generate files without any directory structure inside the dist
directory.
Monorepo directory structure
monorepo\
├─ app\
│ ├─ src\
│ │ └─ index.ts
│ ├─ package.json
│ ├─ tsconfig.json
│ └─ typings.d.ts
└─ lib\
└─ package.json
app/typings.d.ts
declare module "*.json";
app/src/index.ts
// Import from app/package.json
import appPackageJson from '../package.json';
// Import from lib/package.json
import libPackageJson from '../../lib/package.json';
export function run(): void {
console.log(`App name "${appPackageJson.name}" with version ${appPackageJson.version}`);
console.log(`Lib name "${libPackageJson.name}" with version ${libPackageJson.version}`);
}
run();
app/package.json
contents
{
"name": "my-app",
"version": "0.0.1",
...
}
lib/package.json
contents
{
"name": "my-lib",
"version": "1.0.1",
...
}
Now if we compile the project using tsc
, we'll get the following dist
directory structure:
app\
└─ dist\
├─ index.d.ts
└─ index.js
And if we run it using node ./dist
, we'll get the output from both app
and lib
package.json
information:
$ node ./dist
App name "my-app" with version 0.0.1
Lib name "my-lib" with version 1.0.1
You can find the project repository here: https://github.com/clytras/typescript-monorepo
Solution 3:
It is not possible for now. Typescript compiler try to keep your directory structure.
For example, your project look like:
src/
shared/
index.ts
index.ts
package.json
tsconfig.json
Your tsconfig.json
contains:
{
"compilerOptions": {
"outDir": "./build",
"module": "commonjs",
"target": "es6",
"moduleResolution": "node",
"emitDecoratorMetadata": true,
"experimentalDecorators": true,
"noImplicitAny": true,
"sourceMap": true,
"resolveJsonModule": true,
"esModuleInterop": true
},
"include": [
"src/**/*"
]
}
As you see, the file does not include rootDir
property, but when you call tsc
command to compile the project, the output will look like:
build/
shared/
index.js
index.js
The output does not contain src
folder, because in my code, I just import and use inside src
folder, like:
src/index.ts
import someName from './shared';
then, build/index.js
will look like:
...
const shared_1 = __importDefault(require("./shared"));
...
as you see - require("./shared")
, this mean it working fine with build
folder structure.
Your "issue" appeared when you import a "outside" module
import packageJson from '../package.json';
So, what happen with "back" action - '../'? If you hope your output structure will be:
build/
package.json
index.js
then, how do they work with const packageJson = __importDefault(require("../package.json"));
. Then Typescript compiler try to keep project structure:
build/
package.json
src/
index.js
With a monorepo project, I think you need to create declaration files for each library, end then use references
setting in the tsconfig file. Ex:
- In the
./lib01
folder, the lib import./lib02
in their code. Tsconfig file will be like:
{
"compilerOptions": {
"declarationDir": "dist",
"rootDir": "src"
},
"include": ["src/**/*"],
"references": [ // here
{
"path": "../lib02"
}
]
}
- lib02's
tsconfig.json
{
"compilerOptions": {
"declarationDir": "dist",
"rootDir": "src",
"composite": true // importance.
}
}