Creating graph with date and time in axis labels with matplotlib
I have my data in an array of the following structure,
[[1293606162197, 0, 0],
[1293605477994, 63, 0],
[1293605478057, 0, 0],
[1293605478072, 2735, 1249],
[1293606162213, 0, 0],
[1293606162229, 0, 0]]
The first column is epoch time (in ms
), second is y1
and third is y2
. I need a plot with the time on the x-axis, and y1
and y2
on left and right y-axes.
I have been scouring through the documentation but couldn't find any way to get my x-axis ticks to display both date and time, like "28/12 16:48", i.e., "date/month hour:min". All the documentation helps me with is to display dates alone, but that is not what I want. Any help would be appreciated on this.
And, if it may seem like, this is not homework. It is actually a follow up to my previous question, Reading and graphing data read from huge files.
Solution 1:
I hope this helps. I've always had a hard time with matplotlib's dates. Matplotlib requires a float format which is days since epoch. The helper functions num2date
and date2num
along with python builtin datetime
can be used to convert to/from. The formatting business was lifted from this example. You can change an axis on any plot to a date axis using set_major_formatter
.
import numpy as np
from matplotlib import pyplot as plt
from matplotlib import dates
import datetime
a = np.array([
[1293605162197, 0, 0],
[1293605477994, 63, 0],
[1293605478057, 0, 0],
[1293605478072, 2735, 1249],
[1293606162213, 0, 0],
[1293606162229, 0, 0]])
d = a[:,0]
y1 = a[:,1]
y2 = a[:,2]
# convert epoch to matplotlib float format
s = d/1000
ms = d-1000*s # not needed?
dts = map(datetime.datetime.fromtimestamp, s)
fds = dates.date2num(dts) # converted
# matplotlib date format object
hfmt = dates.DateFormatter('%m/%d %H:%M')
fig = plt.figure()
ax = fig.add_subplot(111)
ax.vlines(fds, y2, y1)
ax.xaxis.set_major_locator(dates.MinuteLocator())
ax.xaxis.set_major_formatter(hfmt)
ax.set_ylim(bottom = 0)
plt.xticks(rotation='vertical')
plt.subplots_adjust(bottom=.3)
plt.show()