Try this command:

 grep -v -f file2.csv file1.csv > file3.csv

According to grep manual:

  -f FILE, --file=FILE
          Obtain  patterns  from  FILE,  one  per  line.   The  empty file
          contains zero patterns, and therefore matches nothing.   (-f  is
          specified by POSIX.)

  -v, --invert-match
          Invert the sense of matching, to select non-matching lines.  (-v
          is specified by POSIX.)

As Steeldriver said in his comment is better add also -x and -F that:

  -F, --fixed-strings
          Interpret PATTERN as a  list  of  fixed  strings,  separated  by
          newlines,  any  of  which is to be matched.  (-F is specified by
          POSIX.)
  -x, --line-regexp
          Select  only  those  matches  that exactly match the whole line.
          (-x is specified by POSIX.)

So, better command is:

 grep -xvFf file2.csv file1.csv > file3.csv

This command use file2.csv line as pattern and print line of file1.csv that doesn't match (-v).


In order to be able to use comm, you have to sort the lines first.

comm -23 <(sort file1.csv) <(sort file2.csv) > file3.csv

A python option:

#!/usr/bin/env python3

import sys

def readfile(file):
    with open(file) as src:
        return [line.strip() for line in src.readlines()]

lines_1 = readfile(sys.argv[1]); lines_2 = readfile(sys.argv[2])

for line in lines_1:
    if not line in lines_2:
        print(line)

Output:

1,4,5,6
1,11,13,17

Paste the script into an empty file as extract.py, make it executable and run it by the command:

<script> <file_1> <file_2>

Or, to write it directly to file_3:

<script> <file_1> <file_2> >file_3

Using diff command do grep and no storing required.

Output if lines exist in file1 but not in file2:

$ diff file{1,2}.csv | grep -Po "^< \K.*"
1,4,5,6
1,11,13,17

And output if lines exist in file2 but not in file1, with just changing left angle(<) to right angle(>):

$ diff file{1,2}.csv | grep -Po "^> \K.*"
2,4,9,10
13,14,17,18