Get all inherited classes of an abstract class [duplicate]

Solution 1:

This is such a common problem, especially in GUI applications, that I'm surprised there isn't a BCL class to do this out of the box. Here's how I do it.

public static class ReflectiveEnumerator
{
    static ReflectiveEnumerator() { }

    public static IEnumerable<T> GetEnumerableOfType<T>(params object[] constructorArgs) where T : class, IComparable<T>
    {
        List<T> objects = new List<T>();
        foreach (Type type in 
            Assembly.GetAssembly(typeof(T)).GetTypes()
            .Where(myType => myType.IsClass && !myType.IsAbstract && myType.IsSubclassOf(typeof(T))))
        {
            objects.Add((T)Activator.CreateInstance(type, constructorArgs));
        }
        objects.Sort();
        return objects;
    }
}

A few notes:

• Don't worry about the "cost" of this operation - you're only going to be doing it once (hopefully) and even then it's not as slow as you'd think.
• You need to use Assembly.GetAssembly(typeof(T)) because your base class might be in a different assembly.
• You need to use the criteria type.IsClass and !type.IsAbstract because it'll throw an exception if you try to instantiate an interface or abstract class.
• I like forcing the enumerated classes to implement IComparable so that they can be sorted.
• Your child classes must have identical constructor signatures, otherwise it'll throw an exception. This typically isn't a problem for me.

Solution 2:

Assuming they are all defined in the same assembly, you can do:

IEnumerable<AbstractDataExport> exporters = typeof(AbstractDataExport)
    .Assembly.GetTypes()
    .Where(t => t.IsSubclassOf(typeof(AbstractDataExport)) && !t.IsAbstract)
    .Select(t => (AbstractDataExport)Activator.CreateInstance(t));

Solution 3:

It may not be the elegant way but you can iterate all classes in the assembly and invoke Type.IsSubclassOf(AbstractDataExport) for each one.