Get user's current location
Solution 1:
<?php
$user_ip = getenv('REMOTE_ADDR');
$geo = unserialize(file_get_contents("http://www.geoplugin.net/php.gp?ip=$user_ip"));
$country = $geo["geoplugin_countryName"];
$city = $geo["geoplugin_city"];
?>
Solution 2:
Edited
Change freegeoip.net into ipinfo.io
<?php
function get_client_ip()
{
$ipaddress = '';
if (isset($_SERVER['HTTP_CLIENT_IP'])) {
$ipaddress = $_SERVER['HTTP_CLIENT_IP'];
} else if (isset($_SERVER['HTTP_X_FORWARDED_FOR'])) {
$ipaddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
} else if (isset($_SERVER['HTTP_X_FORWARDED'])) {
$ipaddress = $_SERVER['HTTP_X_FORWARDED'];
} else if (isset($_SERVER['HTTP_FORWARDED_FOR'])) {
$ipaddress = $_SERVER['HTTP_FORWARDED_FOR'];
} else if (isset($_SERVER['HTTP_FORWARDED'])) {
$ipaddress = $_SERVER['HTTP_FORWARDED'];
} else if (isset($_SERVER['REMOTE_ADDR'])) {
$ipaddress = $_SERVER['REMOTE_ADDR'];
} else {
$ipaddress = 'UNKNOWN';
}
return $ipaddress;
}
$PublicIP = get_client_ip();
$json = file_get_contents("http://ipinfo.io/$PublicIP/geo");
$json = json_decode($json, true);
$country = $json['country'];
$region = $json['region'];
$city = $json['city'];
?>
Solution 3:
<?php
$query = @unserialize (file_get_contents('http://ip-api.com/php/'));
if ($query && $query['status'] == 'success') {
echo 'Hey user from ' . $query['country'] . ', ' . $query['city'] . '!';
}
foreach ($query as $data) {
echo $data . "<br>";
}
?>
Try this code using this source. it works!