JavaScript window.open only if the window does not already exist
I'd do it like this - basically store all the referenced opened windows on the function itself. When the function fires, check if the window doesn't exist or has been close - of so, launch the popup. Otherwise, focus on the existing popup window for that request.
function launchApplication(l_url, l_windowName)
{
if ( typeof launchApplication.winRefs == 'undefined' )
{
launchApplication.winRefs = {};
}
if ( typeof launchApplication.winRefs[l_windowName] == 'undefined' || launchApplication.winRefs[l_windowName].closed )
{
var l_width = screen.availWidth;
var l_height = screen.availHeight;
var l_params = 'status=1' +
',resizable=1' +
',scrollbars=1' +
',width=' + l_width +
',height=' + l_height +
',left=0' +
',top=0';
launchApplication.winRefs[l_windowName] = window.open(l_url, l_windowName, l_params);
launchApplication.winRefs[l_windowName].moveTo(0,0);
launchApplication.winRefs[l_windowName].resizeTo(l_width, l_height);
} else {
launchApplication.winRefs[l_windowName].focus()
}
}
You need to perform 2 tests... 1 check if the popup window is defined, and 2 check if it was closed.
if(typeof(winRef) == 'undefined' || winRef.closed){
//create new
winRef = window.open(....);
} else {
//it exists, load new content (if necs.)
winRef.location.href = 'your new url';
//give it focus (in case it got burried)
winRef.focus();
}
You can use something like this in the page that opens the new window:
var newWindow = null;
function launchApplication()
{
// open the new window only if newWindow is null (not opened yet)
// or if it was closed
if ((newWindow == null) || (newWindow.closed))
newWindow = window.open(...);
}
Working code
var newwindow = null;
function popitup(url) {
if ((newwindow == null) || (newwindow.closed)) {
newwindow=window.open(url,'Buy','width=950,height=650,scrollbars=yes,resizable=yes');
newwindow.focus();
} else {
newwindow.location.href = url;
newwindow.focus();
}
}