Find and Replace Inside a Text File from a Bash Command

The easiest way is to use sed (or perl):

sed -i -e 's/abc/XYZ/g' /tmp/file.txt

Which will invoke sed to do an in-place edit due to the -i option. This can be called from bash.

If you really really want to use just bash, then the following can work:

while read a; do
    echo ${a//abc/XYZ}
done < /tmp/file.txt > /tmp/file.txt.t
mv /tmp/file.txt{.t,}

This loops over each line, doing a substitution, and writing to a temporary file (don't want to clobber the input). The move at the end just moves temporary to the original name.

For Mac users:

sed -i '' 's/abc/XYZ/g' /tmp/file.txt (See the comment below why)

File manipulation isn't normally done by Bash, but by programs invoked by Bash, e.g.:

perl -pi -e 's/abc/XYZ/g' /tmp/file.txt

The -i flag tells it to do an in-place replacement.

See man perlrun for more details, including how to take a backup of the original file.

I was surprised when I stumbled over this...

There is a replace command which ships with the "mysql-server" package, so if you have installed it try it out:

# replace string abc to XYZ in files
replace "abc" "XYZ" -- file.txt file2.txt file3.txt

# or pipe an echo to replace
echo "abcdef" |replace "abc" "XYZ"

See man replace for more on this.

This is an old post but for anyone wanting to use variables as @centurian said the single quotes mean nothing will be expanded.

A simple way to get variables in is to do string concatenation since this is done by juxtaposition in bash the following should work:

sed -i -e "s/$var1/$var2/g" /tmp/file.txt