sorting a List of Map<String, String>
I have a list variable created like this:
List<Map<String, String>> list = new ArrayList<Map<String, String>>();
In my Android application, this list gets populated.
just an example:
Map<String, String> map1 = new HashMap<String, String>();
map.put("name", "Josh");
...
Map<String, String> map2 = new HashMap<String, String>();
map.put("name", "Anna");
...
Map<String, String> map3 = new HashMap<String, String>();
map.put("name", "Bernie");
...
list.add(map1);
list.add(map2);
list.add(map3);
I am using list
to show results in a ListView
by extending BaseAdapter
and implementing the various methods.
My problem: I need to sort list
in alphabetical order based on the map's key name
Question: What is a simple way to sort list
in alphabetical order based on the map's key name?
I can't seem to wrap my head around this. I have extracted each name from each Map
into a String
array, and sorted it(Arrays.sort(strArray);
). But that doesn't preserve the other data in each Map
, so i'm not too sure how i can preserve the other mapped values
Solution 1:
The following code works perfectly
public Comparator<Map<String, String>> mapComparator = new Comparator<Map<String, String>>() {
public int compare(Map<String, String> m1, Map<String, String> m2) {
return m1.get("name").compareTo(m2.get("name"));
}
}
Collections.sort(list, mapComparator);
But your maps should probably be instances of a specific class.
Solution 2:
You should implement a Comparator<Map<String, String>>
which basically extracts the "name" value from the two maps it's passed, and compares them.
Then use Collections.sort(list, comparator)
.
Are you sure a Map<String, String>
is really the best element type for your list though? Perhaps you should have another class which contains a Map<String, String>
but also has a getName()
method?
Solution 3:
@Test
public void testSortedMaps() {
Map<String, String> map1 = new HashMap<String, String>();
map1.put("name", "Josh");
Map<String, String> map2 = new HashMap<String, String>();
map2.put("name", "Anna");
Map<String, String> map3 = new HashMap<String, String>();
map3.put("name", "Bernie");
List<Map<String, String>> mapList = new ArrayList<Map<String, String>>();
mapList.add(map1);
mapList.add(map2);
mapList.add(map3);
Collections.sort(mapList, new Comparator<Map<String, String>>() {
public int compare(final Map<String, String> o1, final Map<String, String> o2) {
return o1.get("name").compareTo(o2.get("name"));
}
});
Assert.assertEquals("Anna", mapList.get(0).get("name"));
Assert.assertEquals("Bernie", mapList.get(1).get("name"));
Assert.assertEquals("Josh", mapList.get(2).get("name"));
}
Solution 4:
You need to create a comparator. I am not sure why each value needs its own map but here is what the comparator would look like:
class ListMapComparator implements Comparator {
public int compare(Object obj1, Object obj2) {
Map<String, String> test1 = (Map<String, String>) obj1;
Map<String, String> test2 = (Map<String, String>) obj2;
return test1.get("name").compareTo(test2.get("name"));
}
}
You can see it working with your above example with this:
public class MapSort {
public List<Map<String, String>> testMap() {
List<Map<String, String>> list = new ArrayList<Map<String, String>>();
Map<String, String> myMap1 = new HashMap<String, String>();
myMap1.put("name", "Josh");
Map<String, String> myMap2 = new HashMap<String, String>();
myMap2.put("name", "Anna");
Map<String, String> myMap3 = new HashMap<String, String>();
myMap3.put("name", "Bernie");
list.add(myMap1);
list.add(myMap2);
list.add(myMap3);
return list;
}
public static void main(String[] args) {
MapSort ms = new MapSort();
List<Map<String, String>> testMap = ms.testMap();
System.out.println("Before Sort: " + testMap);
Collections.sort(testMap, new ListMapComparator());
System.out.println("After Sort: " + testMap);
}
}
You will have some type safe warnings because I did not worry about these. Hope that helps.