Adding a parameter to the URL with JavaScript
In a web application that makes use of AJAX calls, I need to submit a request but add a parameter to the end of the URL, for example:
Original URL:
http://server/myapp.php?id=10
Resulting URL:
http://server/myapp.php?id=10&enabled=true
Looking for a JavaScript function which parses the URL looking at each parameter, then adds the new parameter or updates the value if one already exists.
You can use one of these:
- https://developer.mozilla.org/en-US/docs/Web/API/URL
- https://developer.mozilla.org/en/docs/Web/API/URLSearchParams
Example:
var url = new URL("http://foo.bar/?x=1&y=2");
// If your expected result is "http://foo.bar/?x=1&y=2&x=42"
url.searchParams.append('x', 42);
// If your expected result is "http://foo.bar/?x=42&y=2"
url.searchParams.set('x', 42);
A basic implementation which you'll need to adapt would look something like this:
function insertParam(key, value) {
key = encodeURIComponent(key);
value = encodeURIComponent(value);
// kvp looks like ['key1=value1', 'key2=value2', ...]
var kvp = document.location.search.substr(1).split('&');
let i=0;
for(; i<kvp.length; i++){
if (kvp[i].startsWith(key + '=')) {
let pair = kvp[i].split('=');
pair[1] = value;
kvp[i] = pair.join('=');
break;
}
}
if(i >= kvp.length){
kvp[kvp.length] = [key,value].join('=');
}
// can return this or...
let params = kvp.join('&');
// reload page with new params
document.location.search = params;
}
This is approximately twice as fast as a regex or search based solution, but that depends completely on the length of the querystring and the index of any match
the slow regex method I benchmarked against for completions sake (approx +150% slower)
function insertParam2(key,value)
{
key = encodeURIComponent(key); value = encodeURIComponent(value);
var s = document.location.search;
var kvp = key+"="+value;
var r = new RegExp("(&|\\?)"+key+"=[^\&]*");
s = s.replace(r,"$1"+kvp);
if(!RegExp.$1) {s += (s.length>0 ? '&' : '?') + kvp;};
//again, do what you will here
document.location.search = s;
}