Get the year from specified date php

I have a date in this format 2068-06-15. I want to get the year from the date, using php functions. Could someone please suggest how this could be done.

Solution 1:

$date = DateTime::createFromFormat("Y-m-d", "2068-06-15");
echo $date->format("Y");

The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.

Solution 2:

You can use the strtotime and date functions like this:

echo date('Y', strtotime('2068-06-15'));

Note however that PHP can handle year upto 2038

You can test it out here

If your date is always in that format, you can also get the year like this:

$parts = explode('-', '2068-06-15');
echo $parts[0];

Solution 3:

I would use this:

$parts = explode('-', '2068-06-15');
echo $parts[0];

It appears the date is coming from a source where it is always the same, much quicker this way using explode.

Solution 4:

  public function getYear($pdate) {
    $date = DateTime::createFromFormat("Y-m-d", $pdate);
    return $date->format("Y");
}

public function getMonth($pdate) {
    $date = DateTime::createFromFormat("Y-m-d", $pdate);
    return $date->format("m");
}

public function getDay($pdate) {
    $date = DateTime::createFromFormat("Y-m-d", $pdate);
    return $date->format("d");
}