How to get unique device id in flutter?

In Android we have, Settings.Secure.ANDROID_ID. I do not know the iOS equivalent. Is there a flutter plugin or a way to get a unique device id for both Android and IOS in flutter?

Solution 1:

There is a plugin called device_info. You can get it here.

Check the official example here

 static Future<List<String>> getDeviceDetails() async {
    String deviceName;
    String deviceVersion;
    String identifier;
    final DeviceInfoPlugin deviceInfoPlugin = new DeviceInfoPlugin();
    try {
      if (Platform.isAndroid) {
        var build = await deviceInfoPlugin.androidInfo;
        deviceName = build.model;
        deviceVersion = build.version.toString();
        identifier = build.androidId;  //UUID for Android
      } else if (Platform.isIOS) {
        var data = await deviceInfoPlugin.iosInfo;
        deviceName = data.name;
        deviceVersion = data.systemVersion;
        identifier = data.identifierForVendor;  //UUID for iOS
      }
    } on PlatformException {
      print('Failed to get platform version');
    }

//if (!mounted) return;
return [deviceName, deviceVersion, identifier];
}

You can store this UUID in the Keychain. This way you can set an unique ID for your device.

Solution 2:

Null safe code

Use device_info_plus plugin developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
  device_info_plus: ^3.0.1

Create a method:

Future<String?> _getId() async {
  var deviceInfo = DeviceInfoPlugin();
  if (Platform.isIOS) { // import 'dart:io'
    var iosDeviceInfo = await deviceInfo.iosInfo;
    return iosDeviceInfo.identifierForVendor; // unique ID on iOS
  } else {
    var androidDeviceInfo = await deviceInfo.androidInfo;
    return androidDeviceInfo.androidId; // unique ID on Android
  }
}

Usage:

String? deviceId = await _getId();

Solution 3:

I just published a plugin to provide a solution to your problem. It uses Settings.Secure.ANDROID_ID for Android and relies on identifierForVendor and the keychain for iOS to make the behaviour equivalent to Android's. Here's the link.

Solution 4:

Update 1/3/2021: The recommended way is now the extended community plugin called device_info_plus. It supports more platforms than device_info and aims to support all that are supported by flutter. Here is an example usage:

import 'package:flutter/foundation.dart' show kIsWeb;
import 'package:device_info_plus/device_info_plus.dart';
import 'dart:io';

Future<String> getDeviceIdentifier() async {
  String deviceIdentifier = "unknown";
  DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();

  if (Platform.isAndroid) {
    AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
    deviceIdentifier = androidInfo.androidId;
  } else if (Platform.isIOS) {
    IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
    deviceIdentifier = iosInfo.identifierForVendor;
  } else if (kIsWeb) {
    // The web doesnt have a device UID, so use a combination fingerprint as an example
    WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
    deviceIdentifier = webInfo.vendor + webInfo.userAgent + webInfo.hardwareConcurrency.toString();
  } else if (Platform.isLinux) {
    LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
    deviceIdentifier = linuxInfo.machineId;
  } 
  return deviceIdentifier;
}