How to exclude properties from Swift Codable?
Swift's Encodable
/Decodable
protocols, released with Swift 4, make JSON (de)serialization quite pleasant. However, I have not yet found a way to have fine-grained control over which properties should be encoded and which should get decoded.
I have noticed that excluding the property from the accompanying CodingKeys
enum excludes the property from the process altogether, but is there a way to have more fine-grained control?
Solution 1:
The list of keys to encode/decode is controlled by a type called CodingKeys
(note the s
at the end). The compiler can synthesize this for you but can always override that.
Let's say you want to exclude the property nickname
from both encoding and decoding:
struct Person: Codable {
var firstName: String
var lastName: String
var nickname: String?
private enum CodingKeys: String, CodingKey {
case firstName, lastName
}
}
If you want it to be asymmetric (i.e. encode but not decode or vice versa), you have to provide your own implementations of encode(with encoder: )
and init(from decoder: )
:
struct Person: Codable {
var firstName: String
var lastName: String
// Since fullName is a computed property, it's excluded by default
var fullName: String {
return firstName + " " + lastName
}
private enum CodingKeys: String, CodingKey {
case firstName, lastName, fullName
}
// We don't want to decode `fullName` from the JSON
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
firstName = try container.decode(String.self, forKey: .firstName)
lastName = try container.decode(String.self, forKey: .lastName)
}
// But we want to store `fullName` in the JSON anyhow
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
try container.encode(firstName, forKey: .firstName)
try container.encode(lastName, forKey: .lastName)
try container.encode(fullName, forKey: .fullName)
}
}
Solution 2:
Another way to exclude some properties from encoder, separate coding container can be used
struct Person: Codable {
let firstName: String
let lastName: String
let excludedFromEncoder: String
private enum CodingKeys: String, CodingKey {
case firstName
case lastName
}
private enum AdditionalCodingKeys: String, CodingKey {
case excludedFromEncoder
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
let anotherContainer = try decoder.container(keyedBy: AdditionalCodingKeys.self)
firstName = try container.decode(String.self, forKey: .firstName)
lastName = try container.decode(String.self, forKey: .lastName)
excludedFromEncoder = try anotherContainer(String.self, forKey: . excludedFromEncoder)
}
// it is not necessary to implement custom encoding
// func encode(to encoder: Encoder) throws
// let person = Person(firstName: "fname", lastName: "lname", excludedFromEncoder: "only for decoding")
// let jsonData = try JSONEncoder().encode(person)
// let jsonString = String(data: jsonData, encoding: .utf8)
// jsonString --> {"firstName": "fname", "lastName": "lname"}
}
same approach can be used for decoder
Solution 3:
If we need to exclude decoding of a couple of properties from a large set of properties in the structure, declare them as optional properties. Code to unwrapping optionals is less than writing a lot of keys under CodingKey enum.
I would recommend using extensions to add computed instance properties and computed type properties. It separates codable comforming properties from other logic hence provides better readability.
Solution 4:
You can use computed properties:
struct Person: Codable {
var firstName: String
var lastName: String
var nickname: String?
var nick: String {
get {
nickname ?? ""
}
}
private enum CodingKeys: String, CodingKey {
case firstName, lastName
}
}