How do I use a file grep comparison inside a bash if/else statement?
Solution 1:
From grep --help
, but also see man grep:
Exit status is 0 if any line was selected, 1 otherwise; if any error occurs and -q was not given, the exit status is 2.
if grep --quiet MYSQL_ROLE=master /etc/aws/hosts.conf; then
echo exists
else
echo not found
fi
You may want to use a more specific regex, such as ^MYSQL_ROLE=master$
, to avoid that string in comments, names that merely start with "master", etc.
This works because the if takes a command and runs it, and uses the return value of that command to decide how to proceed, with zero meaning true and non-zero meaning false—the same as how other return codes are interpreted by the shell, and the opposite of a language like C.
Solution 2:
if
takes a command and checks its return value. [
is just a command.
if grep -q ...
then
....
else
....
fi
Solution 3:
Note that, for PIPE
being any command or sequence of commands, then:
if PIPE ; then
# do one thing if PIPE returned with zero status ($?=0)
else
# do another thing if PIPE returned with non-zero status ($?!=0), e.g. error
fi
For the record, [ expr ]
is a shell builtin† shorthand for test expr
.
Since grep
returns with status 0 in case of a match, and non-zero status in case of no matches, you can use:
if grep -lq '^MYSQL_ROLE=master' ; then
# do one thing
else
# do another thing
fi
Note the use of -l
which only cares about the file having at least one match (so that grep
returns as soon as it finds one match, without needlessly continuing to parse the input file.)
†on some platforms [ expr ]
is not a builtin, but an actual executable /bin/[
(whose last argument will be ]
), which is why [ expr ]
should contain blanks around the square brackets, and why it must be followed by one of the command list separators (;
, &&
, ||
, |
, &
, newline)
Solution 4:
just use bash
while read -r line
do
case "$line" in
*MYSQL_ROLE=master*)
echo "do your stuff";;
*) echo "doesn't exist";;
esac
done <"/etc/aws/hosts.conf"