promise already under evaluation: recursive default argument reference or earlier problems?

Here is my R code. The functions are defined as:

f <- function(x, T) {
  10 * sin(0.3 * x) * sin(1.3 * x ^ 2) + 0.001 * x ^ 3 + 0.2 * x + 80
}

g <- function(x, T, f=f) {
  exp(-f(x) / T)
}

test <- function(g=g, T=1) { 
  g(1, T)
}

The running error is:

> test()
Error in test() :
promise already under evaluation: recursive default argument reference or earlier problems?

If I substitute the definition of f in that of g, then the error goes away.

I was wondering what the error was? How to correct it if don't substitute the definition of f in that of g? Thanks!

Update:

Thanks! Two questions:

(1) if function test further takes an argument for f, will you add something like test <- function(g.=g, T=1, f..=f){ g.(1,T, f.=f..) } ? In cases with more recursions, is it a good and safe practice adding more .?

(2) if f is a non-function argument, for example g <- function(x, T, f=f){ exp(-f*x/T) } and test <- function(g.=g, T=1, f=f){ g.(1,T, f=f.) }, will using the same name for both formal and actual non-functional arguments a good and safe practice or it may cause some potential trouble?

Formal arguments of the form x=x cause this. Eliminating the two instances where they occur we get:

f <- function(x, T) {
   10 * sin(0.3 * x) * sin(1.3 * x^2) + 0.001 * x^3 + 0.2 * x + 80 
}

g <- function(x, T, f. = f) {  ## 1. note f.
   exp(-f.(x)/T) 
}

test<- function(g. = g, T = 1) {  ## 2. note g.
   g.(1,T) 
}

test()
## [1] 8.560335e-37

If you especify argument evaluation context, you avoid the problem of same name:

f <- function(x) {
  10 * sin(0.3 * x) * sin(1.3 * x ^ 2) + 0.001 * x ^ 3 + 0.2 * x + 80
}
g <- function(x, t=1, f=parent.frame()$f) {
  exp(-f(x) / t)
}
test <- function(g=parent.frame()$g, t=1) { 
  g(1,t)
}
test()
[1] 8.560335e-37