expected value of $x_{(1)} + x_{(4)} - x_{(2)} - x_{(3)}$

Solution 1:

If a fair $6$-sided die is thrown $4$ times with ordered outcomes $(x)_1\leq(x)_2\leq(x)_3\leq(x)_4$ then $(x)_1$ will have the same distribution as $7-(x)_4$ and $(x)_2$ will have the same distribution as $7-(x)_3$.

From this we conclude that:

$$\mathbb E(x)_1=7-\mathbb E(x)_4\text{ and }\mathbb E(x)_2=7-\mathbb E(x)_3$$

Consequently:$$\mathbb E[(x)_1+(x)_4-(x)_2-(x)_3]=7-7=0$$