find the value of the product of roots of this quadratic equation

It is given that one of the roots of the quadratic equation : $x^2 + (p + 3)x - p^2 = 0$, where $p$ is a constant, is negative of the other. The question is : find the value of the product of roots.


We know that this equation has at most two roots in the set of reals. Let's denote them with a and -a. Then your equation is x^2-a^2=0. Therefore p must be equal to -3. Hence the equation is x^2-9=0 and the roots are 3 and -3. So the desired product is -9.