$\lim_{n\to\infty}\frac{floor( x\cdot 10^n)}{10^n}$
Solution 1:
The limit is $x$. The sequence can be squeezed between $a_n=\frac{x10^n}{10^n}=x$ above and $b_n=\frac {x10^n-1}{10^n}$ below. Both limits are equal to $x$.
$\lim_{n\to\infty}\frac{floor( x\cdot 10^n)}{10^n}$
Solution 1:
The limit is $x$. The sequence can be squeezed between $a_n=\frac{x10^n}{10^n}=x$ above and $b_n=\frac {x10^n-1}{10^n}$ below. Both limits are equal to $x$.