How to determine the bounding curve of a moving circular sector?
A point of vocabulary: The generic name of this kind of "bounding curve" is "envelope".
This is not a full answer: it gives, under the parametric representation (1) the biggest part of the equation of the upper envelope.
Take a look at the following picture (obtained with Desmos: you can see an animated version here.
The locus of $C$ is the red curve, the locus of $D$ is the purple curve.
The parameters are
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the radius $r$ of the circular arc,
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the aperture angle $2a$ of this arc,
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the ordinate $b$ of point $F$.
The locus of point $C$ is given under the form of parametric equations that can be seen on the upper left of the figure:
$$\begin{cases}x&=&r\cdot\cos\left(\arctan\left(\frac{-b}{t}\right)+a\right)+t\\y&=&r\cdot\sin\left(\arctan\left(\frac{-b}{t}\right)+a\right)\end{cases} \ \text{where} \ t \ \text{is the abscissa or the arc's center}\tag{1}$$
For point $D$ change $a$ into $-a$.
Explanation about the angles found in (1): let $N$ be the midpoint of arc $LM$. As points $F,G,N$ are aligned, if we denote by $t$ the abscissa of $G$:
$$\text{angle of GN w.r.t.} \ x \ \text{axis} \ = \ \angle AGF = \arctan \frac{AF}{AG}=\arctan \frac{-b}{t}$$
To this angle, we add (resp. subtract) angle $a$ in order to obtain point $M$ (resp. point $L$).
The animation shows that, in the first quadrant, it is essentially this point $C$ that governs the "envelope", with an exception around the origin (in the animation here it is the case for $x<0.5$).
This disruption, calling a specific analysis, slightly increases when $a$ becomes important (say $>\pi/4$). The analysis of this exceptional zone looks possible but more complicated...
Waiting for your reactions.