How do I split an int into its digits?

How can I split an int in c++ to its single numbers? For example, I'd like to split 23 to 2 and 3.

Given the number 12345 :

5 is 12345 % 10
4 is 12345 / 10 % 10
3 is 12345 / 100 % 10
2 is 12345 / 1000 % 10
1 is 12345 / 10000 % 10

I won't provide a complete code as this surely looks like homework, but I'm sure you get the pattern.

Reversed order digit extractor (eg. for 23 will be 3 and 2):

while (number > 0)
{
    int digit = number%10;
    number /= 10;
    //print digit
}

Normal order digit extractor (eg. for 23 will be 2 and 3):

std::stack<int> sd;

while (number > 0)
{
    int digit = number%10;
    number /= 10;
    sd.push(digit);
}

while (!sd.empty())
{
    int digit = sd.top();
    sd.pop();
    //print digit
}

The following will do the trick

void splitNumber(std::list<int>& digits, int number) {
  if (0 == number) { 
    digits.push_back(0);
  } else {
    while (number != 0) {
      int last = number % 10;
      digits.push_front(last);
      number = (number - last) / 10;
    }
  }
}

A simple answer to this question can be:

1. Read A Number "n" From The User.
2. Using While Loop Make Sure Its Not Zero.
3. Take modulus 10 Of The Number "n"..This Will Give You Its Last Digit.
4. Then Divide The Number "n" By 10..This Removes The Last Digit of Number "n" since in int decimal part is omitted.
5. Display Out The Number.

I Think It Will Help. I Used Simple Code Like:

#include <iostream>
using namespace std;
int main()
{int n,r;

    cout<<"Enter Your Number:";
    cin>>n;


    while(n!=0)
    {
               r=n%10;
               n=n/10;

               cout<<r;
    }
    cout<<endl;

    system("PAUSE");
    return 0;
}