Get file content from URL?
Depending on your PHP configuration, this may be a easy as using:
$jsonData = json_decode(file_get_contents('https://chart.googleapis.com/chart?cht=p3&chs=250x100&chd=t:60,40&chl=Hello|World&chof=json'));
However, if allow_url_fopen
isn't enabled on your system, you could read the data via CURL as follows:
<?php
$curlSession = curl_init();
curl_setopt($curlSession, CURLOPT_URL, 'https://chart.googleapis.com/chart?cht=p3&chs=250x100&chd=t:60,40&chl=Hello|World&chof=json');
curl_setopt($curlSession, CURLOPT_BINARYTRANSFER, true);
curl_setopt($curlSession, CURLOPT_RETURNTRANSFER, true);
$jsonData = json_decode(curl_exec($curlSession));
curl_close($curlSession);
?>
Incidentally, if you just want the raw JSON data, then simply remove the json_decode
.
1) local simplest methods
<?php
echo readfile("http://example.com/"); //needs "Allow_url_include" enabled
//OR
echo include("http://example.com/"); //needs "Allow_url_include" enabled
//OR
echo file_get_contents("http://example.com/");
//OR
echo stream_get_contents(fopen('http://example.com/', "rb")); //you may use "r" instead of "rb" //needs "Allow_url_fopen" enabled
?>
2) Better Way is CURL:
echo get_remote_data('http://example.com'); // GET request
echo get_remote_data('http://example.com', "var2=something&var3=blabla" ); // POST request
It automatically handles FOLLOWLOCATION problem + Remote urls: src="./imageblabla.png"
turned into:src="http://example.com/path/imageblabla.png"
Code : https://github.com/tazotodua/useful-php-scripts/blob/master/get-remote-url-content-data.php
Don't forget: to get HTTPS contents, your OPENSSL extension should be enabled in your php.ini. (how to get contents of site use HTTPS)