Concisely starting Mac OS apps from the command line
Solution 1:
Finally I got it:
Add this to your .bash_profile
function foomagick() {
rm -f ~/.foomagick.tmp
ls /Applications/ | grep "\.app" | grep -v iWork | while read APP; do
# clean it up
a=`echo $APP | sed s/\ //g`;
a=`echo $a | sed s/\'//g`;
echo alias ${a%.*}="'open -a \"${APP%.*}\"'" >> ~/.foomagick.tmp
done
source ~/.foomagick.tmp
rm ~/.foomagick.tmp
}
foomagick()
Now the following work:
Skim # open Skim.app
Skim foo.pdf
FireFox http://google.com
FireFox google.com # ERROR. Looks for local file.
Edit by Reid:
I implemented the above as a Python script that makes wrapper scripts instead of aliases. You will need to put ~/bin/mankoffmagic
in your path. If you want the wrappers to be updated automatically, run it regularly from cron or somesuch.
#!/usr/bin/python
#
# This script automagically updates a set of wrapper shell scripts in
# ~/bin/mankoffmagic which call Mac apps installed in /Applications.
#
# Inspired by mankoff's shell alias posted on apple.stackexchange.com; see:
# http://apple.stackexchange.com/questions/4240/concisely-starting-mac-os-apps-from-the-command-line/4257#4257
#
# Notes/Bugs:
#
# 1. Does not follow symlinks (aliases?)
#
# 2. Assumes that application names do not contain double-quotes.
#
# 3. Not very smart about finding the actual binary (it guesses). This is
# wrong sometimes, e.g. Firefox. Probably a deeper understanding of the app
# package structure would fix this.
import copy
import glob
import os
import os.path
import re
BINDIR = os.path.expandvars("$HOME/bin/mankoffmagic")
APP_RE = re.compile(r'(.*)\.app$')
STRIP_RE = re.compile(r'[\W_]+')
def main():
# We aggressively delete everything already in BINDIR, to save the trouble
# of analyzing what should stay
for f in glob.glob("%s/*" % BINDIR):
os.unlink(f)
# Walk /Applications and create a wrapper shell script for each .app dir
for (root, dirs, files) in os.walk("/Applications"):
dirs_real = copy.copy(dirs) # so we can manipulate dirs while looping
for d in dirs_real:
#print "checking %s" % os.path.join(root, d)
m = APP_RE.search(d)
if (m is not None):
#print "Found " + m.group()
dirs.remove(d) # no need to recurse into app
create_script(root, d, m.group(1))
def create_script(path, appdir, appname):
# remove non-alphanumerics and downcase it
wrapper = STRIP_RE.sub('', appname).lower()
wrapper = os.path.join(BINDIR, wrapper)
fp = open(wrapper, "w")
# Twiddle the comments in the script depending on whether you want to
# invoke the binary or use "open" -- the former lets you use any
# command-line args, while the latter is more Mac-like (app puts itself in
# the front, etc.)
fp.write("""
#!/bin/sh
exec "%s/%s/Contents/MacOS/%s" "$@"
#open -a "%s" "$@"
""" % (path, appdir, appname, appname))
fp.close()
os.chmod(wrapper, 0700)
if (__name__ == "__main__"):
main()
Solution 2:
You don't need anything fancy, you already have the answer. Try:
open /Applications/Foo.app bar.pdf
on edit
In light of the comments below, I think my answer would still be relatively similar... I would make a function that overrides open, does a pushd to /Applications
, calls /usr/bin/open $appName.app $args
, does a popd and returns.
I suck at shell scripting but something like below which covers special cases and keeps you using pretty much the same syntax as apple provided for open. I like to keep my environment as clean as possible.
I'm sure the syntax is from outer space:
function open($appName, $args)
{
#if we are calling open without a path like /Applications/TextEdit.app AND
# $appName ends in '.app'
if (!hasParent($appName) && isApp($appName))
{
pushd /Applications
/usr/bin/open ${appName}.app $args &
popd
return
}
#otherwise, use open as normal
/usr/bin/open $appName $args
return
}
on second edit
looking @mankoff's comment on the original question, most of the stuff in the above function would probably be a waste of time since you could just use open -a $appName
. So mankoff probably has the easiest solution and should change his comment to an answer ;)