Solution 1:

$f(x|\mu) = \exp(-\mu) \mu^x/x!$

$\implies l(x|\mu) = \ln{f(x|\mu)} = -\mu + x\ln{\mu} - \sum_{i=1}^{x}i$

$l^{\prime}(x|\mu) = -1 + \frac{x}{\mu}$

$l^{\prime\prime}(x|\mu) = - \frac{x}{\mu^2}$

Fisher information $I(\mu) = -E[l^{\prime\prime}(x|\mu)] = \frac{E[X]}{\mu^2} = \frac{1}{\mu} $