What does a && operator do when there is no left side in C?

I saw a program in C that had code like the following:

static void *arr[1]  = {&& varOne,&& varTwo,&& varThree};

varOne: printf("One") ;
varTwo: printf("Two") ;
varThree: printf("Three") ;

I am confused about what the && does because there is nothing to the left of it. Does it evaluate as null by default? Or is this a special case?

Edit: Added some more information to make the question/code more clear for my question. Thank you all for the help. This was a case of the gcc specific extension.


Solution 1:

It's a gcc-specific extension, a unary && operator that can be applied to a label name, yielding its address as a void* value.

As part of the extension, goto *ptr; is allowed where ptr is an expression of type void*.

It's documented here in the gcc manual.

You can get the address of a label defined in the current function (or a containing function) with the unary operator &&. The value has type void *. This value is a constant and can be used wherever a constant of that type is valid. For example:

void *ptr;
/* ... */
ptr = &&foo;

To use these values, you need to be able to jump to one. This is done with the computed goto statement, goto *exp;. For example,

goto *ptr;

Any expression of type void * is allowed.

As zwol points out in a comment, gcc uses && rather than the more obvious & because a label and an object with the same name can be visible simultaneously, making &foo potentially ambiguous if & means "address of label". Label names occupy their own namespace (not in the C++ sense), and can appear only in specific contexts: defined by a labeled-statement, as the target of a goto statement, or, for gcc, as the operand of unary &&.

Solution 2:

This is a gcc extension, known as "Labels as Values". Link to gcc documentation.

In this extension, && is a unary operator that can be applied to a label. The result is a value of type void *. This value may later be dereferenced in a goto statement to cause execution to jump to that label. Also, pointer arithmetic is permitted on this value.

The label must be in the same function; or in an enclosing function in case the code is also using the gcc extension of "nested functions".

Here is a sample program where the feature is used to implement a state machine:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void)
{
    void *tab[] = { &&foo, &&bar, &&qux };

    // Alternative method
    //ptrdiff_t otab[] = { &&foo - &&foo, &&bar - &&foo, &&qux - &&foo };

    int i, state = 0;

    srand(time(NULL));

    for (i = 0; i < 10; ++i)
    {
        goto *tab[state];

        //goto *(&&foo + otab[state]);

    foo:
        printf("Foo\n");
        state = 2;
        continue;
    bar:
        printf("Bar\n");
        state = 0;
        continue;
    qux:
        printf("Qux\n");
        state = rand() % 3;
        continue;
    }
}

Compiling and execution:

$ gcc -o x x.c && ./x
Foo
Qux
Foo
Qux
Bar
Foo
Qux
Qux
Bar
Foo