Explain Type Assertions in Go
Short answer
In one line:
x.(T)
asserts thatx
is not nil and that the value stored inx
is of typeT
.
Why would I use them:
- to check
x
is nil - to check if it's convertible (assert) to another type
- convert (assert) to another type
What exactly they return:
t := x.(T)
=> t is of typeT
; ifx
is nil, it panics.t,ok := x.(T)
=> ifx
is nil or not of typeT
=>ok
isfalse
otherwiseok
istrue
andt
is of typeT
.
Detailed explanation
Imagine you need to calculate area of 4 different shapes: Circle, Square, Rectangle and Triangle. You may define new types with a new method called Area()
, like this:
type Circle struct {
Radius float64
}
func (t Circle) Area() float64 {
return math.Pi * t.Radius * t.Radius
}
And for Triangle
:
type Triangle struct {
A, B, C float64 // lengths of the sides of a triangle.
}
func (t Triangle) Area() float64 {
p := (t.A + t.B + t.C) / 2.0 // perimeter half
return math.Sqrt(p * (p - t.A) * (p - t.B) * (p - t.C))
}
And for Rectangle
:
type Rectangle struct {
A, B float64
}
func (t Rectangle) Area() float64 {
return t.A * t.B
}
And for Square
:
type Square struct {
A float64
}
func (t Square) Area() float64 {
return t.A * t.A
}
Here you have Circle
, with radius of 1.0, and other shapes with their sides:
shapes := []Shape{
Circle{1.0},
Square{1.772453},
Rectangle{5, 10},
Triangle{10, 4, 7},
}
Interesting! How can we collect them all in one place?
First you need Shape interface
to collect them all in one slice of shape []Shape
:
type Shape interface {
Area() float64
}
Now you can collect them like this:
shapes := []Shape{
Circle{1.0},
Square{1.772453},
Rectangle{5, 10},
Triangle{10, 4, 7},
}
After all, Circle
is a Shape
and Triangle
is a Shape
too.
Now you can print the area of each shape using the single statement v.Area()
:
for _, v := range shapes {
fmt.Println(v, "\tArea:", v.Area())
}
So Area()
is a common interface between all shapes.
Now, how can we calculate and call uncommon method like angles of triangle using above shapes
?
func (t Triangle) Angles() []float64 {
return []float64{angle(t.B, t.C, t.A), angle(t.A, t.C, t.B), angle(t.A, t.B, t.C)}
}
func angle(a, b, c float64) float64 {
return math.Acos((a*a+b*b-c*c)/(2*a*b)) * 180.0 / math.Pi
}
Now it's time to extract Triangle
from above shapes
:
for _, v := range shapes {
fmt.Println(v, "\tArea:", v.Area())
if t, ok := v.(Triangle); ok {
fmt.Println("Angles:", t.Angles())
}
}
Using t, ok := v.(Triangle)
we requested type assertions, meaning we asked the compiler to try to convert v
of type Shape
to type Triangle
, so that if it's successful, the ok
will be true
otherwise false
, and then if it is successful call t.Angles()
to calculate the triangle's three angles.
This is the output:
Circle (Radius: 1) Area: 3.141592653589793
Square (Sides: 1.772453) Area: 3.1415896372090004
Rectangle (Sides: 5, 10) Area: 50
Triangle (Sides: 10, 4, 7) Area: 10.928746497197197
Angles: [128.68218745348943 18.194872338766785 33.12294020774379]
And the whole working sample code:
package main
import "fmt"
import "math"
func main() {
shapes := []Shape{
Circle{1.0},
Square{1.772453},
Rectangle{5, 10},
Triangle{10, 4, 7},
}
for _, v := range shapes {
fmt.Println(v, "\tArea:", v.Area())
if t, ok := v.(Triangle); ok {
fmt.Println("Angles:", t.Angles())
}
}
}
type Shape interface {
Area() float64
}
type Circle struct {
Radius float64
}
type Triangle struct {
A, B, C float64 // lengths of the sides of a triangle.
}
type Rectangle struct {
A, B float64
}
type Square struct {
A float64
}
func (t Circle) Area() float64 {
return math.Pi * t.Radius * t.Radius
}
// Heron's Formula for the area of a triangle
func (t Triangle) Area() float64 {
p := (t.A + t.B + t.C) / 2.0 // perimeter half
return math.Sqrt(p * (p - t.A) * (p - t.B) * (p - t.C))
}
func (t Rectangle) Area() float64 {
return t.A * t.B
}
func (t Square) Area() float64 {
return t.A * t.A
}
func (t Circle) String() string {
return fmt.Sprint("Circle (Radius: ", t.Radius, ")")
}
func (t Triangle) String() string {
return fmt.Sprint("Triangle (Sides: ", t.A, ", ", t.B, ", ", t.C, ")")
}
func (t Rectangle) String() string {
return fmt.Sprint("Rectangle (Sides: ", t.A, ", ", t.B, ")")
}
func (t Square) String() string {
return fmt.Sprint("Square (Sides: ", t.A, ")")
}
func (t Triangle) Angles() []float64 {
return []float64{angle(t.B, t.C, t.A), angle(t.A, t.C, t.B), angle(t.A, t.B, t.C)}
}
func angle(a, b, c float64) float64 {
return math.Acos((a*a+b*b-c*c)/(2*a*b)) * 180.0 / math.Pi
}
Also see:
Type assertions
For an expression x of interface type and a type T, the primary expression
x.(T)
asserts that x is not nil and that the value stored in x is of type T. The notation x.(T) is called a type assertion.
More precisely, if T is not an interface type, x.(T) asserts that the dynamic type of x is identical to the type T. In this case, T must implement the (interface) type of x; otherwise the type assertion is invalid since it is not possible for x to store a value of type T. If T is an interface type, x.(T) asserts that the dynamic type of x implements the interface T.
If the type assertion holds, the value of the expression is the value stored in x and its type is T. If the type assertion is false, a run-time panic occurs. In other words, even though the dynamic type of x is known only at run time, the type of x.(T) is known to be T in a correct program.
var x interface{} = 7 // x has dynamic type int and value 7 i := x.(int) // i has type int and value 7 type I interface { m() } var y I s := y.(string) // illegal: string does not implement I (missing method m) r := y.(io.Reader) // r has type io.Reader and y must implement both I and io.Reader
A type assertion used in an assignment or initialization of the special form
v, ok = x.(T) v, ok := x.(T) var v, ok = x.(T)
yields an additional untyped boolean value. The value of ok is true if the assertion holds. Otherwise it is false and the value of v is the zero value for type T. No run-time panic occurs in this case.
EDIT
Question: What does the assertion x.(T)
return when T is an interface{}
and not a concrete type?
Answer:
It asserts that x is not nil and that the value stored in x is of type T.
E.g. this panics (compile: Success, Run: panic: interface conversion: interface is nil, not interface {}
):
package main
func main() {
var i interface{} // nil
var _ = i.(interface{})
}
And this works (Run: OK):
package main
import "fmt"
func main() {
var i interface{} // nil
b, ok := i.(interface{})
fmt.Println(b, ok) // <nil> false
i = 2
c, ok := i.(interface{})
fmt.Println(c, ok) // 2 true
//var j int = c // cannot use c (type interface {}) as type int in assignment: need type assertion
//fmt.Println(j)
}
Output:
<nil> false
2 true
NOTE: here c
is of type interface {}
and not int
.
See this working sample code with commented outputs:
package main
import "fmt"
func main() {
const fm = "'%T'\t'%#[1]v'\t'%[1]v'\t%v\n"
var i interface{}
b, ok := i.(interface{})
fmt.Printf(fm, b, ok) // '<nil>' '<nil>' '<nil>' false
i = 2
b, ok = i.(interface{})
fmt.Printf(fm, b, ok) // 'int' '2' '2' true
i = "Hi"
b, ok = i.(interface{})
fmt.Printf(fm, b, ok) // 'string' '"Hi"' 'Hi' true
i = new(interface{})
b, ok = i.(interface{})
fmt.Printf(fm, b, ok) // '*interface {}' '(*interface {})(0xc042004330)' '0xc042004330' true
i = struct{}{}
b, ok = i.(interface{})
fmt.Printf(fm, b, ok) // 'struct {}' 'struct {}{}' '{}' true
i = fmt.Println
b, ok = i.(interface{})
fmt.Printf(fm, b, ok) // 'func(...interface {}) (int, error)' '(func(...interface {}) (int, error))(0x456740)' '0x456740' true
i = Shape.Area
b, ok = i.(interface{})
fmt.Printf(fm, b, ok) // 'func(main.Shape) float64' '(func(main.Shape) float64)(0x401910)' '0x401910' true
}
type Shape interface {
Area() float64
}
Common usecase: check if returned error is of a type T.
https://golang.org/ref/spec#Type_assertions
For a single return value assertion: when it fails the program panics.
For a two return values assertion: when it fails second argument is set to false and the program doesn't panic.
A type assertion is the x.(T) notation where x is of interface type and T is a type. Additionally, the actual value stored in x is of type T, and T must satisfy the interface type of x.