Why do you use typedef when declaring an enum in C++?

In C, declaring your enum the first way allows you to use it like so:

TokenType my_type;

If you use the second style, you'll be forced to declare your variable like this:

enum TokenType my_type;

As mentioned by others, this doesn't make a difference in C++. My guess is that either the person who wrote this is a C programmer at heart, or you're compiling C code as C++. Either way, it won't affect the behaviour of your code.

It's a C heritage, in C, if you do :

enum TokenType
{
    blah1   = 0x00000000,
    blah2   = 0X01000000,
    blah3   = 0X02000000
};

you'll have to use it doing something like :

enum TokenType foo;

But if you do this :

typedef enum e_TokenType
{
    blah1   = 0x00000000,
    blah2   = 0X01000000,
    blah3   = 0X02000000
} TokenType;

You'll be able to declare :

TokenType foo;

But in C++, you can use only the former definition and use it as if it were in a C typedef.

You do not need to do it. In C (not C++) you were required to use enum Enumname to refer to a data element of the enumerated type. To simplify it you were allowed to typedef it to a single name data type.

typedef enum MyEnum { 
  //...
} MyEnum;

allowed functions taking a parameter of the enum to be defined as

void f( MyEnum x )

instead of the longer

void f( enum MyEnum x )

Note that the name of the typename does not need to be equal to the name of the enum. The same happens with structs.

In C++, on the other hand, it is not required, as enums, classes and structs can be accessed directly as types by their names.

// C++
enum MyEnum {
   // ...
};
void f( MyEnum x ); // Correct C++, Error in C