Why doesn't Ruby support i++ or i-- (increment/decrement operators)?
Solution 1:
Here is how Matz(Yukihiro Matsumoto) explains it in an old thread:
Hi,
In message "[ruby-talk:02706] X++?"
on 00/05/10, Aleksi Niemelä <[email protected]> writes:
|I got an idea from http://www.pragprog.com:8080/rubyfaq/rubyfaq-5.html#ss5.3
|and thought to try. I didn't manage to make "auto(in|de)crement" working so
|could somebody help here? Does this contain some errors or is the idea
|wrong?
(1) ++ and -- are NOT reserved operator in Ruby.
(2) C's increment/decrement operators are in fact hidden assignment.
They affect variables, not objects. You cannot accomplish
assignment via method. Ruby uses +=/-= operator instead.
(3) self cannot be a target of assignment. In addition, altering
the value of integer 1 might cause severe confusion throughout
the program.
matz.
Solution 2:
One reason is that up to now every assignment operator (i.e. an operator which changes a variable) has a =
in it. If you add ++
and --
, that's no longer the case.
Another reason is that the behavior of ++
and --
often confuse people. Case in point: The return value of i++
in your example would actually be 1, not 2 (the new value of i
would be 2, however).
Solution 3:
It's not conventional in OO languages. In fact, there is no ++
in Smalltalk, the language that coined the term "object-oriented programming" (and the language Ruby is most strongly influenced by). What you mean is that it's conventional in C and languages closely imitating C. Ruby does have a somewhat C-like syntax, but it isn't slavish in adhering to C traditions.
As for why it isn't in Ruby: Matz didn't want it. That's really the ultimate reason.
The reason no such thing exists in Smalltalk is because it's part of the language's overriding philosophy that assigning a variable is fundamentally a different kind of thing than sending a message to an object — it's on a different level. This thinking probably influenced Matz in designing Ruby.
It wouldn't be impossible to include it in Ruby — you could easily write a preprocessor that transforms all ++
into +=1
. but evidently Matz didn't like the idea of an operator that did a "hidden assignment." It also seems a little strange to have an operator with a hidden integer operand inside of it. No other operator in the language works that way.
Solution 4:
I think there's another reason: ++
in Ruby wouldn't be remotely useful as in C and its direct successors.
The reason being, the for
keyword: while it's essential in C, it's mostly superfluous in Ruby. Most of the iteration in Ruby is done through Enumerable methods, such as each
and map
when iterating through some data structure, and Fixnum#times
method, when you need to loop an exact number of times.
Actually, as far as I have seen, most of the time +=1
is used by people freshly migrated to Ruby from C-style languages.
In short, it's really questionable if methods ++
and --
would be used at all.
Solution 5:
I think Matz' reasoning for not liking them is that it actually replaces the variable with a new one.
ex:
a = SomeClass.new def a.go 'hello' end # at this point, you can call a.go # but if you did an a++ # that really means a = a + 1 # so you can no longer call a.go # as you have lost your original
Now if somebody could convince him that it should just call #succ! or what not, that would make more sense, and avoid the problem. You can suggest it on ruby core.