What does $0 and $1 mean in Swift Closures?
Solution 1:
$0
is the first parameter passed into the closure. $1
is the second parameter, etc. That closure you showed is shorthand for:
let sortedNumbers = numbers.sort { (firstObject, secondObject) in
return firstObject > secondObject
}
Solution 2:
TL;DR
Swift 5.5
$0
and$1
are Closure’s first and second shorthand arguments (a.k.a.Shorthand Argument Names
orSAN
for short). The shorthand argument names are automatically provided by Swift. The first argument can be referenced by$0
, the second argument can be referenced by$1
, the third one by$2
, and so on.
As you know, a Closure is a self-contained block of functionality (a function without name) that can be passed around and used in your code. Closure has different names in other programming languages as well as slight differences in meaning – it's Lambda in Python and Kotlin, or Block in C and Obj-C.
Shortening a Closure
let coffee: [String] = ["Cappuccino", "Espresso", "Latte", "Ristretto"]
1. Normal Function
func backward(_ n1: String, _ n2: String) -> Bool {
return n1 > n2
}
var reverseOrder = coffee.sorted(by: backward)
/* RESULT: ["Ristretto", "Latte", "Espresso", "Cappuccino"] */
2. Inline Closure Expression
reverseOrder = coffee.sorted(by: { (n1: String,
n2: String) -> Bool in return n1 > n2 } )
3. Inferring Type From Context
reverseOrder = coffee.sorted(by: { n1, n2 in return n1 > n2 } )
4. Implicit Returns from Single-Expression Closures
reverseOrder = coffee.sorted(by: { n1, n2 in n1 > n2 } )
5. Shorthand Argument Names
reverseOrder = coffee.sorted(by: { $0 > $1 } )
/* $0 and $1 are closure’s first and second String arguments. */
6. Operator Methods
reverseOrder = coffee.sorted(by: >)
/* RESULT: ["Ristretto", "Latte", "Espresso", "Cappuccino"] */
Higher Order Function map
with dot notation
let companies = ["bmw", "kfc", "ibm", "htc"]
let uppercased = companies.map { (item) -> String in item.uppercased() }
/* RESULT: ["BMW", "KFC", "IBM", "HTC"] */
Shorthand Argument Name in HOF map
let uppercased = companies.map { $0.uppercased() }
/* RESULT: ["BMW", "KFC", "IBM", "HTC"] */
SAN in HOF filter
with remainder operator
let numbers: [Int] = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
let filteredNumbers = numbers.filter { ($0 % 2) == 0 }
print(filteredNumbers)
/* RESULT: [2, 4, 6, 8, 10] */
SAN in Variadic functions
Variadic functions are ones that accept any number of parameters. Shorthand Argument Names are perfect for such cases.
fileprivate func dessert(_ fruits: String...) -> Bool {
return fruits.contains { $0 == "Apple" }
}
let contains = dessert("Mango", "Durian", "apple")
print(contains)
/* RESULT: false */
Repeating $0
let cubedNumber = { $0 * $0 * $0 } (25)
print(cubedNumber)
/* RESULT: 25^3 = 15625 */
Three Shorthand Argument Names – $0
, $1
, $2
let math: (Int8, Int8, Int8) -> Int8 = { $0 + $1 - $2 }
func feedClosure() -> (Int8, Int8, Int8) -> Int8 {
return math
}
feedClosure()(10, 20, 100)
/* RESULT: (10 + 20 - 100) = -70 */
Five SANs – $0
, $1
, $2
, $3
, $4
let factorial = { $0 * $1 * $2 * $3 * $4 } (1, 2, 3, 4, 5)
print(factorial)
/* RESULT: 5! = 120 */
Key Path Expression
In Swift 5.2 you can access parameters of every instance via key path expression:
struct Lighter {
let manufacturer: String
let refillable: Bool
}
let zippo = Lighter(manufacturer: "Zippo", refillable: true)
let cricket = Lighter(manufacturer: "Cricket", refillable: false)
let lighters: [Lighter] = [zippo, cricket]
let refillableOnes = lighters.map(\.refillable)
print(refillableOnes)
/* RESULT: [true, false] */
Of course, you can alternatively use a familiar syntax:
Regular syntax – $0.property
:
let refillableOnes = lighters.map { $0.refillable }
print(refillableOnes)
/* RESULT: [true, false] */
Shorthand Argument Name with a subscript
let arrays: [[String]] = [["Hello", "Hola"], ["world", "mundo"]]
let helloWorld = arrays.compactMap { $0[0] }
print(helloWorld)
/* RESULT: ["Hello", "world"] */
One more example with a subscript:
let dictionaries: [[Int8: Any?]] = [[1: "x"], [2: nil], [3: "z"]]
let values = dictionaries.compactMap { $0[$0.startIndex].value }
print(values)
/* RESULT: ["x", "z"] */
Or look at this example:
let sett: Set<String> = ["One", "", "Three"]
sett.map {
switch $0.isEmpty {
case true:
print("Empty")
case false:
print("Element \($0) isn't empty")
}
}
/* RESULT: "Element Three isn't empty" */
/* "Empty" */
/* "Element One isn't empty" */
Shorthand Argument Name in Completion Handler
let completionHandler: ((Bool) -> Void)? = {
if $0 {
print("It is true, sister...")
} else {
print("False")
}
}
completionHandler?(true)
/* RESULT: It is true, sister... */
Regular syntax, however, is as following:
let completionHandler: ((Bool) -> Void)? = { sayTheTruth in
if sayTheTruth {
print("It is true, sister...")
} else {
print("False")
}
}
completionHandler?(false)
/* RESULT: False */
SAN in ForEach structure in SwiftUI
let columns: [GridItem] = Array(repeating: .init(.fixed(70)), count: 5)
var body: some View {
ScrollView {
LazyVGrid(columns: columns) {
ForEach((1...10), id: \.self) {
Text("\($0)").frame(maxWidth: .infinity)
}
}
}
}
/* RESULT: 1 2 3 4 5 */
/* 6 7 8 9 10 */
Operator Method vs SAN
Operator Method:
let records: [Int] = [110, 108, 107, 109, 108]
public func averageSpeed(records: [Int]) throws -> Int {
let average = records.reduce(0, +) / records.count
return average
}
try averageSpeed(records: records)
/* RESULT: 108 */
Shorthand Argument Names $0 and $1:
public func averageSpeed(records: [Int]) throws -> Int {
let average = records.reduce(0) { $0 + $1 } / records.count
return average
}
try averageSpeed(records: records)
/* RESULT: 108 */
Swift vs Kotlin vs Python
Also, let's see how Kotlin's lambda is similar to Swift's closure:
Swift
let element: [String] = ["Argentum","Aurum","Platinum"]
let characterCount = element.map { $0.count }
print(characterCount)
/* RESULT: [8, 5, 8] */
Kotlin
Often Kotlin's lambda expression has only one parameter with implicit name: it
.
val element = listOf("Argentum","Aurum","Platinum")
val characterCount = element.map { it.length }
println(characterCount)
/* RESULT: [8, 5, 8] */
But in Python there's no equivalent of Shorthand Argument Name
.
Python
element = ["Argentum","Aurum","Platinum"]
characterCount = list(map(lambda x: len(x), element))
print(characterCount)
# RESULT: [8, 5, 8]