Calculate $\frac13+\frac29+\frac{1}{27}+\frac{2}{81}+\frac{1}{243}+\frac{2}{729}+\ldots$

How can we calculate the formula for the following series?

$\frac13+\frac29+\frac{1}{27}+\frac{2}{81}+\frac{1}{243}+\frac{2}{729}+\ldots$

I'm not quite sure what type of series it is anyway. It doesn't look geometric. Is there any strategy/procedure to follow in order to calculate the formula for a series of numbers?


Solution 1:

If you are looking for the infinite sum, it is the sum of two geometric series: $$ \sum_{k=1}^\infty\frac1{3^k}+\sum_{k=1}^\infty\frac1{9^k}=\frac12+\frac18=\frac58 $$

Solution 2:

If we add neighbouring pairs, we get $$\frac{5}{9}+\frac{5}{81}+\frac{5}{729}+\cdots.$$ This is an infinite geometric series with first term $\frac{5}{9}$ and common ratio $\frac{1}{9}$.

By the usual formula for the sum of an infinite geometric progression, the sum is $$\frac{5}{9}\frac{1}{1-\frac{1}{9}}.$$ This can be simplified to $\frac{5}{8}$.