TypeScript: Property does not exist on type '{}'

Solution 1:

You can assign the any type to the object:

let bar: any = {};
bar.foo = "foobar"; 

Solution 2:

Access the field with array notation to avoid strict type checking on single field:

data['propertyName']; //will work even if data has not declared propertyName

Alternative way is (un)cast the variable for single access:

(<any>data).propertyName;//access propertyName like if data has no type

The first is shorter, the second is more explicit about type (un)casting

You can also totally disable type checking on all variable fields:

let untypedVariable:any= <any>{}; //disable type checking while declaring the variable
untypedVariable.propertyName = anyValue; //any field in untypedVariable is assignable and readable without type checking

Note: This would be more dangerous than avoid type checking just for a single field access, since all consecutive accesses on all fields are untyped

Solution 3:

let propertyName= data['propertyName'];