Convert bytes to int?
I'm currently working on an encryption/decryption program and I need to be able to convert bytes to an integer. I know that:
bytes([3]) = b'\x03'
Yet I cannot find out how to do the inverse. What am I doing terribly wrong?
Solution 1:
Assuming you're on at least 3.2, there's a built in for this:
int.from_bytes
(bytes
,byteorder
, *,signed=False
)...
The argument
bytes
must either be a bytes-like object or an iterable producing bytes.The
byteorder
argument determines the byte order used to represent the integer. Ifbyteorder
is"big"
, the most significant byte is at the beginning of the byte array. Ifbyteorder
is"little"
, the most significant byte is at the end of the byte array. To request the native byte order of the host system, usesys.byteorder
as the byte order value.The
signed
argument indicates whether two’s complement is used to represent the integer.
## Examples:
int.from_bytes(b'\x00\x01', "big") # 1
int.from_bytes(b'\x00\x01', "little") # 256
int.from_bytes(b'\x00\x10', byteorder='little') # 4096
int.from_bytes(b'\xfc\x00', byteorder='big', signed=True) #-1024
Solution 2:
Lists of bytes are subscriptable (at least in Python 3.6). This way you can retrieve the decimal value of each byte individually.
>>> intlist = [64, 4, 26, 163, 255]
>>> bytelist = bytes(intlist) # b'@\x04\x1a\xa3\xff'
>>> for b in bytelist:
... print(b) # 64 4 26 163 255
>>> [b for b in bytelist] # [64, 4, 26, 163, 255]
>>> bytelist[2] # 26
Solution 3:
int.from_bytes( bytes, byteorder, *, signed=False )
doesn't work with me I used function from this website, it works well
https://coderwall.com/p/x6xtxq/convert-bytes-to-int-or-int-to-bytes-in-python
def bytes_to_int(bytes):
result = 0
for b in bytes:
result = result * 256 + int(b)
return result
def int_to_bytes(value, length):
result = []
for i in range(0, length):
result.append(value >> (i * 8) & 0xff)
result.reverse()
return result