I have an array of integers, how do I use each one in a mysql query (in php)? [duplicate]
Solution 1:
As with nearly all "How do I do SQL from within PHP" questions - You really should use prepared statements. It's not that hard:
$ids = array(2, 4, 6, 8);
// prepare an SQL statement with a single parameter placeholder
$sql = "UPDATE MyTable SET LastUpdated = GETDATE() WHERE id = ?";
$stmt = $mysqli->prepare($sql);
// bind a different value to the placeholder with each execution
for ($i = 0; $i < count($ids); $i++)
{
$stmt->bind_param("i", $ids[$i]);
$stmt->execute();
echo "Updated record ID: $id\n";
}
// done
$stmt->close();
Alternatively, you can do it like this:
$ids = array(2, 4, 6, 8);
// prepare an SQL statement with multiple parameter placeholders
$params = implode(",", array_fill(0, count($ids), "?"));
$sql = "UPDATE MyTable SET LastUpdated = GETDATE() WHERE id IN ($params)";
$stmt = $mysqli->prepare($sql);
// dynamic call of mysqli_stmt::bind_param hard-coded eqivalent
$types = str_repeat("i", count($ids)); // "iiii"
$args = array_merge(array($types), $ids); // ["iiii", 2, 4, 6, 8]
call_user_func_array(array($stmt, 'bind_param'), ref($args)); // $stmt->bind_param("iiii", 2, 4, 6, 8)
// execute the query for all input values in one step
$stmt->execute();
// done
$stmt->close();
echo "Updated record IDs: " . implode("," $ids) ."\n";
// ----------------------------------------------------------------------------------
// helper function to turn an array of values into an array of value references
// necessary because mysqli_stmt::bind_param needs value refereces for no good reason
function ref($arr) {
$refs = array();
foreach ($arr as $key => $val) $refs[$key] = &$arr[$key];
return $refs;
}
Add more parameter placeholders for other fields as you need them.
Which one to pick?
The first variant works with a variable number of records iteratively, hitting the database multiple times. This is most useful for UPDATE and INSERT operations.
The second variant works with a variable number of records too, but it hits the database only once. This is much more efficient than the iterative approach, obviously you can only do the same thing to all affected records. This is most useful for SELECT and DELETE operations, or when you want to UPDATE multiple records with the same data.
Why prepared statements?
- Prepared statements are a lot safer because they make SQL injection attacks impossible. This is the primary reason to use prepared statements, even if it is more work to write them. A sensible habit to get into is: Always use prepared statements, even if you think it's "not really necessary." Neglect will come and bite you (or your customers).
- Re-using the same prepared statement multiple times with different parameter values is more efficient than sending multiple full SQL strings to the database, because the database only needs to compile the statement once and can re-use it as well.
- Only parameter values are sent to the database on
execute()
, so less data needs to go over the wire when used repeatedly.
In longer loops the execution time difference between using a prepared statement and sending plain SQL will become noticeable.
Solution 2:
Using the "IN" Clause
Might be what you're after
$ids = array(2,4,6,8);
$ids = implode($ids);
$sql="SELECT * FROM my_table WHERE id IN($ids);";
mysql_query($sql);
otherwise, what's wrong with
$ids = array(2,4,6,8);
foreach($ids as $id) {
$sql="SELECT * FROM my_table WHERE ID = $id;";
mysql_query($sql);
}
Solution 3:
Amen to Tomalak's comment on statements.
However, if you do not wish to use mysqli, you can always use intval() to prevent injection:
$ids = array(2, 4, 6, 8);
for ($i = 0; $i < count($ids); $i++)
{
mysql_query("UPDATE MyTable SET LastUpdated = GETDATE() WHERE id = " . intval($ids[$i]));
}
Solution 4:
$values_filtered = array_filter('is_int', $values);
if (count($values_filtered) == count($values)) {
$sql = 'update table set attrib = 'something' where someid in (' . implode(',', $values_filtered) . ');';
//execute
} else {
//do something
}