"Integer number too large" error message for 600851475143

public class Three {
    public static void main(String[] args) {
        Three obj = new Three();
        obj.function(600851475143);
    }

    private Long function(long  i) {
        Stack<Long> stack = new Stack<Long>();

        for (long j = 2; j <= i; j++) {
            if (i % j == 0) {
                stack.push(j);
            }
        }
        return stack.pop();
    }
}

When the code above is run, it produces an error on the line obj.function(600851475143);. Why?

Solution 1:

600851475143 cannot be represented as a 32-bit integer (type int). It can be represented as a 64-bit integer (type long). long literals in Java end with an "L": 600851475143L

Solution 2:

Append suffix L: 23423429L.

By default, java interpret all numeral literals as 32-bit integer values. If you want to explicitely specify that this is something bigger then 32-bit integer you should use suffix L for long values.

Solution 3:

You need to use a long literal:

obj.function(600851475143l);  // note the "l" at the end

But I would expect that function to run out of memory (or time) ...