How can I open an Excel file in Python?

Solution 1:

Edit:
In the newer version of pandas, you can pass the sheet name as a parameter.

file_name =  # path to file + file name
sheet =  # sheet name or sheet number or list of sheet numbers and names

import pandas as pd
df = pd.read_excel(io=file_name, sheet_name=sheet)
print(df.head(5))  # print first 5 rows of the dataframe

Check the docs for examples on how to pass sheet_name:
https://pandas.pydata.org/pandas-docs/stable/generated/pandas.read_excel.html

Old version:
you can use pandas package as well....

When you are working with an excel file with multiple sheets, you can use:

import pandas as pd
xl = pd.ExcelFile(path + filename)
xl.sheet_names

>>> [u'Sheet1', u'Sheet2', u'Sheet3']

df = xl.parse("Sheet1")
df.head()

df.head() will print first 5 rows of your Excel file

If you're working with an Excel file with a single sheet, you can simply use:

import pandas as pd
df = pd.read_excel(path + filename)
print df.head()

Solution 2:

Try the xlrd library.

[Edit] - from what I can see from your comment, something like the snippet below might do the trick. I'm assuming here that you're just searching one column for the word 'john', but you could add more or make this into a more generic function.

from xlrd import open_workbook

book = open_workbook('simple.xls',on_demand=True)
for name in book.sheet_names():
    if name.endswith('2'):
        sheet = book.sheet_by_name(name)

        # Attempt to find a matching row (search the first column for 'john')
        rowIndex = -1
        for cell in sheet.col(0): # 
            if 'john' in cell.value:
                break

        # If we found the row, print it
        if row != -1:
            cells = sheet.row(row)
            for cell in cells:
                print cell.value

        book.unload_sheet(name)