How to convert dictionary to array

Solution 1:

You can use a for loop to iterate through the dictionary key/value pairs to construct your array:

var myDict: [String : Int] = ["attack" : 1, "defend" : 5, "block" : 12]

var arr = [String]()

for (key, value) in myDict {
    arr.append("\(key) \(value)")
}

Note: Dictionaries are unordered, so the order of your array might not be what you expect.

In Swift 2 and later, this also can be done with map:

let arr = myDict.map { "\($0) \($1)" }

This can also be written as:

let arr = myDict.map { "\($0.key) \($0.value)" }

which is clearer if not as short.

Solution 2:

The general case for creating an array out of ONLY VALUES of a dictionary in Swift 3 is (I assume it also works in older versions of swift):

let arrayFromDic = Array(dic.values.map{ $0 })

Example:

let dic = ["1":"a", "2":"b","3":"c"]

let ps = Array(dic.values.map{ $0 })

print("\(ps)")

for p in ps {
    print("\(p)")
}

Solution 3:

If you like concise code and prefer a functional approach, you can use the map method executed on the keys collection:

let array = Array(myDict.keys.map { "\($0) \(myDict[$0]!)" })

or, as suggested by @vacawama:

let array = myDict.keys.array.map { "\($0) \(myDict[$0]!)" }

which is functionally equivalent

Solution 4:

With Swift 5

var myDict:[String : Int] = ["attack" : 1, "defend" : 5, "block" : 12]

let arrayValues = myDict.values.map({$0})
let arrayKeys = myDict.keys.map({$0})